如何从Objective-C的NSString中获取前N个单词? [英] How to get the first N words from a NSString in Objective-C?

问题描述

给定字符串，最简单的方法是什么

What's the simplest way, given a string:

NSString *str = @"Some really really long string is here and I just want the first 10 words, for example";

导致NSString带有前 N 个单词(例如10个)?

to result in an NSString with the first N (e.g., 10) words?

如果str短于N，我还要确保它不会失败.

I'd also like to make sure it doesn't fail if the str is shorter than N.

推荐答案

如果单词用空格分隔:

NSInteger nWords = 10;
NSRange wordRange = NSMakeRange(0, nWords);
NSArray *firstWords = [[str componentsSeparatedByString:@" "] subarrayWithRange:wordRange];

如果要在所有空白处都打断:

if you want to break on all whitespace:

NSCharacterSet *delimiterCharacterSet = [NSCharacterSet whitespaceAndNewlineCharacterSet];
NSArray *firstWords = [[str componentsSeparatedByCharactersInSet:delimiterCharacterSet] subarrayWithRange:wordRange];

然后

NSString *result = [firstWords componentsJoinedByString:@" "];

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