如何创建结构的NSMutableArray? [英] How can I create an NSMutableArray of structs?

问题描述

我创建了这样的结构

typedef struct Node {
    NSString* Description;
    NSString* AE;
    NSString* IP;
    NSString*  Port;
} Node;

我需要创建此Node结构的NSMutableArray，我需要知道如何将节点的对象创建到NSMutableArray的路径检索它并读取例如端口.

I need to create NSMutableArray of this Node structure I need to know how create object of node path it to the NSMutableArray retrieve it and read for example the port.

推荐答案

您只能将Objective-C对象存储在NSMutableArray中.

You can only store Objective-C objects in an NSMutableArray.

您可以采取的一种方法是使用标准C数组:

One route you can take is to use a standard C array:

unsigned int array_length = ...;
Node** nodes = malloc(sizeof(Node *) * array_length);

另一种方法是将结构包装在Objective-C对象中:

Another route is to wrap the structure in an Objective-C object:

@interface NodeWrapper : NSObject {
   @public

   Node *node;
}
- (id) initWithNode:(Node *) n;
@end

@implementation NodeWrapper

- (id) initWithNode:(Node *) n {
  self = [super init];
  if(self) {
     node = n;
  }
  return self;
}

- (void) dealloc {
  free(node);
  [super dealloc];
}

@end

然后，将NodeWrapper对象添加到NSMutableArray中，如下所示:

Then, you'd add NodeWrapper objects to your NSMutableArray like this:

Node *n = (Node *) malloc(sizeof(Node));
n->AE = @"blah";
NodeWrapper *nw = [[NodeWrapper alloc] initWithNode:n];
[myArray addObject:nw];
[nw release];

要从NodeWrapper中检索Node，只需执行以下操作:

To retrieve the Node from the NodeWrapper, you'd simply do this:

Node *n = nw->node;

或

Node n = *(nw->node);

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