在Promise中返回Observable [英] Return Observable inside the Promise

问题描述

您能告诉我如何在这里退回Observable吗?我尝试了很多方法.但是还没有成功.

Could you tell me how can I return Observable here? I have tried many ways. But no success yet.

[ts]声明的类型既不是'void'也不是'any'的函数必须 返回一个值.

[ts] A function whose declared type is neither 'void' nor 'any' must return a value.

  deleteInvite(inviteId):Observable<HttpResponse<Object>> {
    this.getHttpHeader().then(headers => {
      return this.http.post(this.apiURL + "/deleteInvite", inviteId, { observe: "response", headers: headers })
    }).catch(err => {
      console.error(err);
    });
  }

  async getHttpHeader() {
    const accessToken = await this.getJWTToken();
    let headers = new HttpHeaders().set('Authorization', `Bearer ${accessToken}`);
    return headers;
  }

推荐答案

FOR rxjs版本:6.0.0起

import { from } from 'rxjs';

 deleteInvite(inviteId):Observable<HttpResponse<Object>> {
    return from(this.getHttpHeader()).pipe(
        switchMap(headers => {
            return this.http.post(this.apiURL + "/deleteInvite", inviteId, { observe: "response", headers: headers })
        }),
        catchError(err => {
            console.error(err);
        })
    );
}

对于旧版本的rxjs:

For older versions of rxjs:

使用fromPromise

import { fromPromise } from 'rxjs/observable/fromPromise';


deleteInvite(inviteId):Observable<HttpResponse<Object>> {
    return fromPromise(this.getHttpHeader()).pipe(
        switchMap(headers => {
            return this.http.post(this.apiURL + "/deleteInvite", inviteId, { observe: "response", headers: headers })
        }),
        catchError(err => {
            console.error(err);
        })
    );
}

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