如何从mli文件自动生成存根? [英] How to auto-generate stubs from mli file?

问题描述

假设我有一些接口文件mylib.mli之类的

Suppose I have some interface file mylib.mli like

var foo      : 'a list -> int
val bar      : f:('a -> 'b) -> 'a list -> 'b list
val baz      : f:('a -> bool) -> 'a list -> 'a list
val frobnitz : init:'acc -> f:('acc -> 'a -> 'acc) -> 'a list -> 'acc
val frobozz  : 'a list -> 'a list -> 'a list
val quux     : 'a list list -> 'a list

是否有一种自动的方法来生成相应的mylib.ml作为存根的集合? (存根"是指最小的接口实现功能".)

Is there an automated way to generate the corresponding mylib.ml as a collection of stubs? (By "stub" I mean a "minimal, interface-implementing function".)

推荐答案

AFAIK，目前没有这样的工具.也许是因为手动进行这项工作并不繁重.编写存根的最简单方法是:

AFAIK, there is no such tool currently written. Maybe, because it is not a big work to do it manually. The easiest way to write a stub is:

let foo = failwith "not implemented"

或者您可以通过以下方式制作

or you can just make it in a following way

let stub _ = failwith "unimplemented"

let foo = stub
let bar = stub
...

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