如果-else循环错误，则嵌套-ocaml [英] nested if -else loop error - ocaml

问题描述

我正在尝试为我的代码制定一个多次if-else循环.

I am trying to work out a multiple if-else loop for my code.

我以前的代码是:

let rec appendtolist n list b  =
    let f x =
        if ( b == 0 ) then x
        else (append (appendtocode n (List.hd list)) (appendtolist n (List.tl list) (b-1)))
    in
        f list
    ;;

带有嵌套循环的修改后的代码:

Modified code with nested loops:

let rec appendtolist n list b =
    let f x =
         if b < 0 then x
         else if (b == 0) then appendtocode n (List.hd list) (b-1)
         else appendtocode n (List.hd list) :: appendtolist n (List.tl list) (b-1)
    in
        f list
    ;;

但是我得到这个错误:

This function is applied to too many arguments, maybe you forgot a `;'

我的代码在语法上似乎是正确的.这是在OCaml中实现嵌套循环的正确方法吗? 我遵循了一个在网上找到if-elseif循环的示例，该示例运行良好.

My code seems to be syntactically correct. Is this the right way to implement a nested loop in OCaml?? I followed an example for if-elseif loop found online which worked fine.

我最终需要输出x，该列表是此函数中对appendtocode和appendtolist的所有递归调用之后形成的列表.

I need to finally output x which is the list formed after all the recursive calls to appendtocode and appendtolist in this function.

我在哪里出错了?

请指导.

谢谢.

推荐答案

在您的第一个代码示例中，您像这样调用appendtocode:

In your first code sample you're calling appendtocode like this:

appendtocode n (List.hd list)

所以我假设appendtocode是一个带有2个参数的函数.

So I assume that appendtocode is a function taking 2 arguments.

在第二个步骤中，您将这样称呼它:

In the second you're calling it like this:

appendtocode n (List.hd list) (b-1)

因此，您在这里使用3个参数来调用它.由于只需要两个，因此您会收到一条错误消息，告诉您您使用了太多的参数来调用它.

So here you're calling it with 3 arguments. Since it only takes two, you get an error message telling you that you're calling it with too many arguments.

PS:如果语句不是循环

PS: If statements aren't loops.

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