如何删除“工作表"节点保持其内容完整无缺? [英] How can I delete the "sheet" node keeping its content intact?
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问题描述
我想从表单视图中删除节点<sheet></sheet>
.例如,我有以下视图:
I would like to remove the node <sheet></sheet>
from a form view. For instance, I have this view:
<record id="view_account_period_form" model="ir.ui.view">
<field name="name">account.period.form</field>
<field name="model">account.period</field>
<field name="arch" type="xml">
<form string="Account Period">
<header>
[...]
</header>
<sheet>
<group>
<group>
<field name="name"/>
<field name="fiscalyear_id" widget="selection"/>
<label for="date_start" string="Duration"/>
<div>
<field name="date_start" class="oe_inline" nolabel="1"/> -
<field name="date_stop" nolabel="1" class="oe_inline"/>
</div>
</group>
<group>
<field name="code"/>
<field name="special"/>
<field name="company_id" widget="selection" groups="base.group_multi_company"/>
</group>
</group>
</sheet>
</form>
</field>
</record>
我想在没有节点的其他视图中进行转换,但将所有元素保留在其中:
I would like to convert it in this other view without the node, but keeping all the elements within it:
<record id="view_account_period_form" model="ir.ui.view">
<field name="name">account.period.form</field>
<field name="model">account.period</field>
<field name="arch" type="xml">
<form string="Account Period">
<header>
[...]
</header>
<group>
<group>
<field name="name"/>
<field name="fiscalyear_id" widget="selection"/>
<label for="date_start" string="Duration"/>
<div>
<field name="date_start" class="oe_inline" nolabel="1"/> -
<field name="date_stop" nolabel="1" class="oe_inline"/>
</div>
</group>
<group>
<field name="code"/>
<field name="special"/>
<field name="company_id" widget="selection" groups="base.group_multi_company"/>
</group>
</group>
</form>
</field>
</record>
有可能还是我需要再次覆盖完整的代码?
Is that possible or I need to override the complete code again?
也许类似于:
<xpath expr="//form/sheet" position="replace">
<!-- [...] -->
</xpath>
Git Hub中有一个未解决的问题,要求在此处解决,但我认为也许有人知道如何在不编写Odoo新功能的情况下做到这一点.
There is an open issue in Git Hub asking for solving this here, but I think that maybe anyone knows how to do it without programming a new feature in Odoo.
推荐答案
只需使用fields_view_get:
Just use fields_view_get:
from lxml import etree
def fields_view_get(self, cr, uid, view_id=None, view_type='form', context=None, toolbar=False, submenu=False):
res = models.Model.fields_view_get(self, cr, uid, view_id=view_id, view_type=view_type, context=context, toolbar=toolbar, submenu=submenu)
if view_type == 'form':
doc = etree.XML(res['arch'])
for sheet in doc.xpath("//sheet"):
parent = sheet.getparent()
index = parent.index(sheet)
for child in sheet:
parent.insert(index, child)
index += 1
parent.remove(sheet)
res['arch'] = etree.tostring(doc)
return res
在发生oe_chatting的情况下得到改善
improved in case of oe_chatting presence
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