如何将std :: ofstream重定向到std :: cout? [英] How can I redirect a std::ofstream to std::cout?

问题描述

我正在使用一些代码，这些代码使用类型为std::ofstream*的全局调试记录器.我想将其重定向到std :: cout，因为我是实时使用代码，而不是为其设计的批处理方法.

I'm working with some code that uses a global debug logger that is of type std::ofstream*. I would like to redirect this to std::cout since I'm using the code in realtime, as opposed to a batch method for which it was designed.

是否可以将其使用的全局std::ofstream*指针重定向到std::cout?我知道std::ofstream是从std::ios继承的，它允许人们使用rdbuf()方法更改流缓冲区，但不幸的是，它似乎std::ofstream重新定义了rdbuf()方法，这使得以下代码无法编译:

Is it possible to redirect the global std::ofstream* pointer it uses to std::cout? I know std::ofstream inherits from std::ios, which allows one to change the stream buffer using the rdbuf() method, but unfortunately it appears std::ofstream redefines the rdbuf() method, which makes the following code not compile:

gOsTrace = new std::ofstream();
gOsTrace->rdbuf(std::cout.rdbuf());

还有另一种方法可以重定向gOsTrace对象以指向cout吗?

Is there another way to redirect the gOsTrace object to point to cout?

推荐答案

具体IOStream流类的rdbuf()方法隐藏了std::ios中声明的方法.您需要明确的限定条件才能找到基类重载:

The rdbuf() method of the concrete IOStream stream classes hide the one declared in std::ios. You will need an explicit qualification in order to find the base class overload:

gOsTrace->basic_ios<char>::rdbuf(std::cout.rdbuf());

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