首次打开时，使用VB.net创建Access 07 DB始终会运行“修复" [英] Creating Access 07 DB with VB.net always runs Repair when opening it the first time

问题描述

我有一个VB.NET(Visual Studio 2010)应用程序，该应用程序以编程方式创建Access 07数据库，然后将CSV文件导入为新的Access表.创建数据库，并且导入CSV都没有问题.该代码使用ADOX.Catalog创建数据库，并使用带有ACE的OleDb.OleDbConnection导入CSV.一切都很好，除了我第一次打开Access DB.当我从台式机(Office 07)启动Access 07时，屏幕右下方的绿色修复"进度条显示了大约5秒钟.这仅在我第一次打开数据库时发生.数据库和表可以正常工作，但是Access绝对可以解决问题.我可以每次重新创建此行为.第一次打开数据库时如何避免维修?任何想法都会有所帮助.

I have a VB.NET (Visual Studio 2010) app that creates an Access 07 database programmatically, then imports a CSV file as a new Access table. The DB gets created, and the CSV gets imported with no problems. The code uses ADOX.Catalog to create the database, and an OleDb.OleDbConnection with ACE to import the CSV. All is well, except the first time I open the Access DB. When I launch Access 07 from my desktop (Office 07), I get the green "repair" progress bar at the bottom right of the screen for about 5 seconds. It only happens the first time I open the DB. The DB and tables work fine, but Access is definitely fixing something. I can recreate this behavior every time. How can I avoid the repair when opening the DB the first time? Any ideas would be helpful.

Public Function CreateTaxDatabase(ByVal DatabaseFullPath As String) As Boolean

  Dim bAns As Boolean
  Dim cat As ADOX.Catalog

  Try
     '' check if file exists
     If System.IO.File.Exists(DatabaseFullPath) Then
        '' delete the old file
        System.IO.File.Delete(DatabaseFullPath)
     End If

     Dim sCreateString As String
     cat = New ADOX.Catalog()
     sCreateString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" & DatabaseFullPath
     cat.Create(sCreateString)

     '' close the connection
     Dim connection As ADODB.Connection = DirectCast(cat.ActiveConnection, ADODB.Connection)
     connection.Close()
     bAns = True
  Catch Excep As System.Runtime.InteropServices.COMException
     bAns = False
  Finally
     cat = Nothing
  End Try
  Return bAns
End Function

Sub ImportCSV(dbPath As String, CSVPath As String, CSVFile as String)

  Dim conn As OleDb.OleDbConnection = Nothing
  Dim SQL As String = ""

  Try
     conn = New OleDb.OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + dbPath)
     If conn.State = ConnectionState.Closed Then
        conn.Open()
     End If
  Catch ex As Exception
     MsgBox(ex.Message, MsgBoxStyle.Exclamation + MsgBoxStyle.OkOnly, "Error Connecting to Database")
     If conn.State = ConnectionState.Open Then
        conn.Close()
     End If
 Return
  End Try

  SQL = "SELECT * INTO Table1 FROM [Text;FMT=Delimited;HDR=Yes;CharacterSet=ANSI;DATABASE=" + CSVPath + "].[" + CSVFile + "]"

  Try
     Dim SQLCmd As OleDb.OleDbCommand = conn.CreateCommand
     SQLCmd.CommandText = SQL
     SQLCmd.ExecuteNonQuery()
     Application.DoEvents()
  Catch ex As Exception
     SQL = "There was an error executing the following SQL Statement:" + vbCrLf + _
        SQL + vbCrLf + "Error - " + Trim(Str(Err.Number)) + " " + Err.Description
     MsgBox(SQL, MsgBoxStyle.Exclamation + MsgBoxStyle.OkOnly, "SQL Error")
  Finally
     If conn.State = ConnectionState.Open Then
        conn.Close()
     End If
     If Not IsNothing(conn) Then
        conn = Nothing
     End If
  End Try
End Sub

推荐答案

这似乎可以解决问题

Public Sub CompactRepairDB(DBPath As String)
   '' compact and repair DB
   Dim AccessApp As Microsoft.Office.Interop.Access.Application = New Microsoft.Office.Interop.Access.Application()
   Dim TempDB = GetFilePath(DBPath) + "Compact1.ACCDB"

   DeleteFile(TempDB)
   AccessApp.OpenCurrentDatabase(DBPath)
   AccessApp.CloseCurrentDatabase()
   AccessApp.CompactRepair(DBPath, TempDB)
   AccessApp.Quit()
   DeleteFile(DBPath)
   '' rename Compact1 to Original DB Name
   My.Computer.FileSystem.RenameFile(TempDB, GetFileName(DBPath))
End Sub

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