symfony easyadmin一对多形式 [英] symfony easyadmin one to many form
问题描述
我是easyadmin软件包的新手,我在寻找是否有可能直接从父对象添加子对象 所以我有3个对象: -食谱
i am new to the easyadmin bundle and i am looking if it is possible to add childs directly from the parent object So i got 3 objects : - Recipe
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe
*
* @ORM\Table(name="recipe")
* @ORM\Entity(repositoryClass="AppBundle\Repository\RecipeRepository")
*/
class Recipe
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=100, nullable=true)
*/
private $name;
/**
* @var \DateTime
*
* @ORM\Column(name="createdon", type="datetime", nullable=true)
*/
private $createdon;
/**
* @var string
*
* @ORM\Column(name="description", type="text", nullable=true)
*/
private $description;
/**
* @var string
*
* @ORM\Column(name="version", type="string", length=5, nullable=true)
*/
private $version;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="recipe")
*/
private $recipeproducts;
...
-Recipe_Product(具有要输入的数量和单位作为属性)
-Recipe_Product (which has quantity and unit as attributes to enter)
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe_Product
*
* @ORM\Table(name="recipe__product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\Recipe_ProductRepository")
*/
class Recipe_Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="quantity", type="decimal", precision=10, scale=2, nullable=true)
*/
private $quantity;
/**
* @ORM\ManyToOne(targetEntity="Recipe", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="recipeid", referencedColumnName="id")
* })
*/
private $recipe;
/**
* @ORM\ManyToOne(targetEntity="Product", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Productid", referencedColumnName="id")
* })
*/
private $product;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Unitid", referencedColumnName="id")
* })
*/
private $unit;
...
当然还有一个 -产品.
and of course a - Product.
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Product
*
* @ORM\Table(name="product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\ProductRepository")
*/
class Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=255)
*/
private $name;
/**
* @var string
*
* @ORM\Column(name="ref", type="string", length=25)
*/
private $ref;
/**
* @var string
*
* @ORM\Column(name="ref4stat", type="string", length=25)
*/
private $ref4Stat;
/**
* @var int
*
* @ORM\Column(name="size", type="integer")
*/
private $size;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="unitid", referencedColumnName="id")
* })
*/
private $unit;
/**
* @ORM\ManyToOne(targetEntity="ProductType", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="producttypeid", referencedColumnName="id")
* })
*/
private $producttype;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="product")
*/
private $recipeproducts;
...
在编辑配方时,我希望能够直接添加新的recipe_product系列,但是我还没有找到一种方法来实现这一目标...
When editing a Recipe, i would like to be able to add directly a new recipe_product line but i haven t found a way to do that...
有人有主意吗?
添加于14/10: 我找到了一种呈现表格的方式... 在我的easyadmin配置文件中,我创建了以下条目:
Added on 14/10: I found a way to render the form... in my easyadmin config file, i created the following entry:
Recipe:
class: AppBundle\Entity\Recipe
form:
fields:
- name
- beer
- version
- description
- createdon
- { property: 'recipeproducts', label: 'Ingredients', type: 'collection', type_options: {entry_type: 'AppBundle\Form\Recipe_ProductType', by_reference: false} }
,表单代码为
<?php
namespace AppBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\HiddenType;
class Recipe_ProductType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('product')
->add('quantity')
->add('unit')
;
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'AppBundle\Entity\Recipe_Product'
));
}
}
呈现表单(我猜这两个实体之间未创建链接,但必须在管理控制器中)
which renders the form (that don t create the link between the 2 entities but that must be in the Admin controller i guess)
推荐答案
好,我找到了解决方法...
Ok, i found the solution...
查看此链接: Symfony 3.0嵌套实体未保存
基本上symfony生成器无法正确生成add函数...
Basically symfony generator did not generate the add function correctly...
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