opencv 2-如何仅计算两个图像之间的平移和缩放? [英] opencv 2 - How can I calculate ONLY the translation and scale between two images?

问题描述

我正在寻找一种使用opencv仅计算两个图像之间的平移和缩放的方法.我只遇到了一个刚性变换实现，该实现将比例尺信息与旋转绑定在一起，而我对此并不感兴趣.

I'm looking for a way to calculate only the translation and scale between two images using opencv. I've only encountered a rigid transform implementation which bundles the scale information with the rotation, which I'm not interested in.

您如何建议我这样做?

注意，在下面的代码中，两个非常相等的角度不是，实际上是angle2 = 2 * angle.我不知道为什么:

Notice, in the following code the two surpassingly equal angles are not, actually angle2 = 2 * angle. which I'm not sure why:

    cv::Mat rigid_mat = cv::estimateRigidTransform(prevMatGray, thisMatGray, false);
    float tx = rigid_mat.at<float>(0,2);
    float ty = rigid_mat.at<float>(1,2);

    float a = rigid_mat.at<float>(0,0);
    float b = rigid_mat.at<float>(0,1);

    float c = rigid_mat.at<float>(1,0);
    float d = rigid_mat.at<float>(1,1);

    float sX = [BTImageProcessing sign:a] * sqrtf(powf(a,2) + powf(b,2));
    float sY = [BTImageProcessing sign:d] * sqrt(powf(c,2) + powf(d,2));
    float alpha = atan2f(c, d);
    float alpha2 = atan2f(-b, a);


+ (int)sign:(float)num{
    return num > 0 ? 1 : -1;
}

推荐答案

您可以使用此处(sx，sy，xc，yc)，并且无需旋转.

You can use estimateRigidTransform() to compute an optimal affine transformation [A|b] (a 2x3 floating-point matrix) between two 2D point sets. Next, you should decompose the transformation matrix into scaling and translation, like here (sx, sy, xc, yc) and don't care with rotation.

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