我如何能得到2字母表7数字1字母格式的字符串，正则表达式在.NET [英] how can I get 2 alphabet 7 numeric 1 alphabet format for a string in regex in .net

问题描述

例如，对于格式为aa1231231c

example for the format is aa1231231c

推荐答案

嗯，看起来像：

[a-zA-Z]{2}[0-9]{7}[a-zA-Z]

给我。当然，这取决于你所说的字母和数字的意思是 - 上面只涉及ASCII字母和数字，没有口音，没有其他类型的数字等你

to me. Of course it depends on what you mean by "alphabet" and "numeric" - the above only deals with ASCII letters and digits, with no accents, no other types of digits etc. You

请注意，有替代办法，如使用 \ D 为任意数字和 \ p {L〕匹配任意字母;如果你真的只的希望的ASCII字母和数字，虽然，我会用上面以明确什么是允许的。

Note that there are alternative approaches such as using \d for "any digit" and \p{L} to match "any letter"; if you really only want the ASCII letters and digits though, I'd use the above to make it obvious exactly what's allowed.

您可以匹配在code整个字符串，或使用 ^ 和 $ 来在EX pression迫使它：

You can either match that as the whole string in code, or use ^ and $ to force it in the expression:

^[a-zA-Z]{2}[0-9]{7}[a-zA-Z]$

将prevent你的模式被发现在其他的文字中间。

That will prevent your pattern being found in the middle of other text.

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