为什么openCV Mat.at与原始矩阵不匹配 [英] why openCV Mat.at doesn't match original matrix

问题描述

我有一个二维双精度型矩阵.

I have a two dimension double type matrix.

双**结果； (8334 * 34尺寸)

double ** results; (8334*34 size)

这些值类似于: 0.00211094，0，6.10098e-006 .......

The values are something like: 0.00211094, 0, 6.10098e-006.......

我使用代码Mat m = Mat(ROW，COL，CV_64F，results)，

I use the code Mat m = Mat(ROW, COL, CV_64F, results),

但是当我检查元素时，我发现值不匹配，并且m中的值非常奇怪，类似于5.325e-344(太小了！)

but when I check the element, I found the values are not match, and the value in m in very strange, something like 5.325e-344 (too small!)

cout<(0,0)！=结果[0] [0]

cout<(0,0) != result[0][0]

我测试了一个小的矩阵，答案与矩阵匹配.

I test a small matrix, and the answer match the matrix.

double a = 0.00211094;
double b = 6.10098e-006;
double c=0;
double aa[3][3] = {{a, b, c}, {0.4, 0.5, 0.6}, {0.7, 0.8, 0.9}};
Mat m = Mat(3, 3, CV_64F, aa);

cout<<m.at<double>(0,1)<<endl;

谁能告诉我为什么?这是我的C ++内存问题(结果矩阵太大吗?)?

Could anyone tell me why? Is this my C++ memory's problem (results matrix is too large?)?

推荐答案

只能在Mat中设置小矩阵.

only small matrix could be set into Mat.

所以我尝试将每个元素设置为mat.

So I try to set each element into mat.

for(i...){
for(j...){
    m.at<double>(i,j) =results[i][j];
}
}

它有效.

有趣！

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