如何在Asmack，Android中使用户在线或离线 [英] how to get user online or offline in asmack, android

问题描述

可能重复:
XMPP aSmack-如何可以获取当前用户状态(离线/在线/离开/等)?

Possible Duplicate:
XMPP aSmack - How can I get the current user state (offline/online/away/etc.)?

我正在基于asmack lib的Android上开发聊天应用程序.我在ListView上显示所有用户，但我使用图像显示在线/离线用户.但是它仅返回离线图像，即使用户在线，这也是我的代码

I am developing chat app on Android base on asmack lib. I display all the user on the ListView but I use an image to show online/offline user. But It return offline image only, even the user is online, here is my code

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    // setContentView(R.layout.buddies);

    Controller.getInstance().roster = Controller.getInstance().connection.getRoster();
//  ArrayList<Buddy> buddies = new ArrayList<Buddy>();
    Collection<RosterEntry> entries = Controller.getInstance().roster.getEntries();
    Controller.getInstance().buddyList = new Buddy[entries.size()];

    int i = 0;

    for (RosterEntry r : entries) {
        Buddy bud = new Buddy();
        VCard card = new VCard();
        try {
            ProviderManager.getInstance().addIQProvider("vCard",
                    "vcard-temp", new VCardProvider());
            card.load(Controller.getInstance().connection, r.getUser());
        } catch (XMPPException e) {
            Log.e("ChatOnAndroid", e.getMessage() + " " + r.getUser() + " "
                    + e.getLocalizedMessage());
        }
        bud.jid = r.getUser();
        bud.name = r.getName();
        bud.status = Controller.getInstance().roster.getPresence(r.getUser());
        Controller.getInstance().buddies.add(bud);


        Controller.getInstance().buddyList[i++] = bud;
    }
    BuddyAdapter adapter = new BuddyAdapter(this, R.layout.buddy, Controller.getInstance().buddies);

    setListAdapter(adapter);


     /*
      * list = (ListView) findViewById(R.id.buddiesList);
     * list.setAdapter(adapter);
     */
}

@Override
protected void onListItemClick(ListView l, View v, int position, long id) {     
    startActivity(new Intent(this, Conferences.class));
}

public class BuddyAdapter extends ArrayAdapter<Buddy> {

    private ArrayList<Buddy> items;

    public BuddyAdapter(Context context, int textViewResourceId,
            ArrayList<Buddy> items) {
        super(context, textViewResourceId, items);
        this.items = items;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View v = convertView;
        if (v == null) {
            LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            v = vi.inflate(R.layout.buddy, null);
        }
        Buddy buddy = items.get(position);

        if (buddy != null) {
            TextView tt = (TextView) v.findViewById(R.id.buddyName);
            ImageView iv = (ImageView) v.findViewById(R.id.buddyThumb);
            //buddy.status = Controller.getInstance().roster.getPresence(buddy.jid);

            if (buddy.status != null) {
                buddy.img = R.drawable.status_online;
                iv.setImageResource(buddy.img);
            } else if (buddy.status == null) {
                buddy.img = R.drawable.status_offline;
                iv.setImageResource(buddy.img);
            }

            //iv.setImageResource(buddy.img);
            if (tt != null) {
                tt.setText(buddy.name);
            }
        }
        return v;
    }
}

推荐答案

有一种方法可以查找用户的离线/在线状态.可以通过寻求用户的存在来完成.这是代码片段:

There is a means to find the offline/online status of the user. It can be done by seeking the PRESENCE OF THE USER. Here is the code snippet :

///这是在线或离线的方式

//here is how you can get is ONLINE or OFFLINE

        Presence availability = roster.getPresence(user);

这是获取其在线状态模式的代码，即如果用户可用，那么他是离开"，请勿打扰"模式或在线聊天".

And here is the code to get its presence mode i.e if user is available then is he AWAY,DONOT DISTURB MODE or ONLINE For CHAT.

public int retrieveState_mode(Mode userMode, boolean isOnline) {
        int userState = 0;
        /** 0 for offline, 1 for online, 2 for away,3 for busy*/
        if(userMode == Mode.dnd) {
            userState = 3;
        } else if (userMode == Mode.away || userMode == Mode.xa) {

            userState = 2;
        } else if (isOnline) {
            userState = 1;
        }
        return userState;
    }

您可以将此状态保存为数组列表:-

you can save this state in an array list as :-

mFriendsDataClass.friendState = retrieveState_mode(availability.getMode(),availability.isAvailable());

如果您在聊天类型应用程序中对xmpp/smack有任何疑问，请告诉我

Please let me know if you have any queries regarding xmpp/smack in chat type application

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