是否有跨平台的方式在Python中打开文件浏览器? [英] Is there a cross-platform way to open a file browser in Python?

问题描述

我在考虑 webbrowser 模块的思路，但是对于文件浏览器.在Windows中，我想打开资源管理器，在Linux上，我要打开nautilus，在KDE上，打开Konqueror，等等.如果可以避免的话，我不愿对其进行混淆. ;-)

I'm thinking something along the lines of the webbrowser module, but for file browsers. In Windows I'd like to open explorer, in GNOME on Linux I want to open nautilus, Konqueror on KDE, etc. I'd prefer not to kludge it up if I can avoid it. ;-)

推荐答案

如果我可以避免的话，我宁愿不加思索.

I'd prefer not to kludge it up if I can avoid it.

Weeell我认为您将需要一点平台嗅探功能，但希望不会像可怕的命令嗅探webbrowser模块那么多.这是它的第一个刺路:

Weeell I think you are going to need a little bit of platform-sniffing kludge, but hopefully not as much as the ghastly command-sniffing webbrowser module. Here's a first stab at it:

if sys.platform=='win32':
    subprocess.Popen(['start', d], shell= True)

elif sys.platform=='darwin':
    subprocess.Popen(['open', d])

else:
    try:
        subprocess.Popen(['xdg-open', d])
    except OSError:
        # er, think of something else to try
        # xdg-open *should* be supported by recent Gnome, KDE, Xfce

请注意，win32版本当前将无法使用文件名中的空格. 错误2304 可能与此有关，但是参数转义和Windows shell(cmd /c ...)，因为您不能嵌套双引号，也不能^-转义引号或空格.我根本找不到从命令行引用和运行cmd /c start C:\Documents and Settings的任何方式.

Note the win32 version will currently fail for spaces in filenames. Bug 2304 might be something to do with that, but there does seem to be a basic problem with parameter escaping and the Windows shell (cmd /c ...), in that you can't nest double-quotes and you can't ^-escape quotes or spaces. I haven't managed to find any way to quote and run cmd /c start C:\Documents and Settings from the command line at all.

ETA re nosklo的评论:仅在Windows上，有一种内置方法:

ETA re nosklo's comment: on Windows only, there is a built-in way to do it:

if sys.platform=='win32':
    os.startfile(d)

这是一种非常不错的替代解决方案，它可以找到外壳并用它打开一个文件夹，您现在不需要了，但我将继续.(部分原因是它可能用于其他用途，但主要是因为我花了时间打字该死的东西！)

Here's the not-very-nice alternative solution to find the shell and open a folder with it, which you shouldn't now need, but I'll leave in. (Partly because it might be of use for something else, but mostly because I spent the time to type the damned thing!)

if sys.platform=='win32':
    import _winreg
    path= r'SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon')
    for root in (_winreg.HKEY_CURRENT_USER, _winreg.HKEY_LOCAL_MACHINE):
        try:
            with _winreg.OpenKey(root, path) as k:
                value, regtype= _winreg.QueryValueEx(k, 'Shell')
        except WindowsError:
            pass
        else:
            if regtype in (_winreg.REG_SZ, _winreg.REG_EXPAND_SZ):
                shell= value
            break
    else:
        shell= 'Explorer.exe'
    subprocess.Popen([shell, d])

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