Ada:运算符不直接可见 [英] Ada : operator is not directly visible
问题描述
我正在使用GNAT GPS studio IDE以便对Ada进行一些培训.我的包裹可见性有问题.
I'm using GNAT GPS studio IDE in order to train a bit in Ada. I'm having an issue with package visibility.
首先,我在名为"DScale.ads"的文件中指定一个包含以下类型的包:
First I specify a package in a file called "DScale.ads" containing a type:
package DScale is
type DMajor is (D, E, F_Sharp, G, A, B, C_Sharp);
end DScale;
然后,我在另一个文件("Noteworthy.ads")中指定一个程序包,该程序包定义将使用DScale程序包的DMajor类型的过程:
Then I specify in a different file ("Noteworthy.ads") a package that defines a procedure that will use the DMajor type of the DScale package:
with Ada.Text_IO;
with DScale;
package NoteWorthy is
procedure Note;
end NoteWorthy;
最后,在"Noteworthy.adb"中,为软件包"Noteworthy"提供了软件包主体:
Finally in "Noteworthy.adb" I provide the package body for the package "Noteworthy":
with Ada.Text_IO; use Ada.Text_IO;
package body Noteworthy is
procedure Note is
package ScaleIO is new Enumeration_IO(DScale.DMajor);
thisNote : DScale.DMajor := DScale.D;
begin
ScaleIO.Get(thisNote);
if thisNote = DScale.DMajor'First then
Put_Line("First note of scale.");
end if;
end Note;
begin
null;
end NoteWorthy;
如果按原样保留代码,则在值得注意的"包的正文中,"ifthisNote = DScale.DMajor'First then"语句将收到操作员无法直接看到"错误.
If I leave the code as-is, I will get an "operator not directly visible" error for the "if thisNote = DScale.DMajor'First then" statement in the body of the "Noteworthy" package.
是否有一种无需使用"use"或"use type"子句来绕过此错误的方法?
Is there a way to bypass this error without using a "use" or "use type" clause?
谢谢.
推荐答案
您的问题(至少)有两个答案.
There are (at least) two answers to your question.
1:
if DScale."=" (thisNote, DScale.DMajor'First) then
2:
function "=" (Left, Right : DScale.DMajor) return Boolean renames DScale.DMajor;
...
if thisNote = DScale.DMajor'First then
但是您为什么要使用这些选项之一而不是:
But why would you use one of those options instead of:
use type DScale.DMajor;
...
if thisNote = DScale.DMajor'First then
这篇关于Ada:运算符不直接可见的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!