&之间的差异(&)和&&或| (管道)和||在Objective-C中? [英] Difference between & (ampersand) and && or | (pipe) and || in Objective-C?

问题描述

我想知道Objective-C是否关心我是否撰写&或&& ;?我相信一个&号会导致或应该导致，如果LEFT一侧已经为假，则不会对右侧进行评估.

I wonder if Objective-C does care about whether I write & or &&? I believe one ampersand (&) would or should cause that if the LEFT side is already false, then the right side won't be evaluated.

这是否适用于Objective-C?

Does this apply to Objective-C?

推荐答案

是.运算符在C和Objective-C中的功能相同.

Yes. The operators function identically in C and Objective-C.

就像在C(或C ++，如果您使用的是Objective-C ++)中一样，&和|是按位的，而&&和||是逻辑(和短路)的.按位运算符(&和|)不是短路.

Just like in C (or C++, if you're using Objective-C++) & and | are bit-wise and && and || are logical (and short-circuit). Bit-wise operators (& and |) are not short-circuit.

请参见使用C和C ++的操作符

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