需要Oracle SQL按日期划分日期/时间范围 [英] Need Oracle SQL to split up date/time range by day

问题描述

我希望能得到一些帮助，以帮助我编写一些我自己编写的SQL程序.

I am hoping to get some help to write some SQL that I have had no success writing myself.

我有一张数据表:

ID    StartDate             EndDate
1     01/01/2000 04:30 PM   01/03/2000 06:15 AM
2     01/04/2000 08:10 AM   01/04/2000 07:25 AM
3     01/05/2000 11:00 AM   01/06/2000 03:45 AM

我需要获得以下信息:

ID    StartDate             EndDate
1     01/01/2000 04:30 PM   01/01/2000 11:59 PM
1     01/02/2000 12:00 AM   01/02/2000 11:59 PM
1     01/03/2000 12:00 AM   01/03/2000 06:15 AM
2     01/04/2000 08:10 AM   01/04/2000 07:25 AM
3     01/05/2000 11:00 AM   01/05/2000 11:59 PM
3     01/06/2000 12:00 AM   01/06/2000 03:45 AM

换句话说，按日期划分日期范围.在SQL中甚至有可能吗?

In other words, split up date ranges by day. Is this even possible in SQL?

我的数据库是Oracle 11G R2，由于某些情况，我担心不能使用PL/SQL.

My database is Oracle 11G R2 and I am afraid due to circumstances I cannot use PL/SQL.

推荐答案

可以在SQL中执行此操作.有两个技巧.首先是生成一系列数字，您可以使用connect对CTE进行处理.

It is possible to do this in SQL. There are two tricks. The first is generating a series of numbers, which you can do with a CTE using connect.

第二个是将正确的逻辑放在一起以扩展日期，同时保留正确的开始和结束时间.

The second is putting together the right logic to expand the dates, while keeping the right times for the beginning and end.

以下是示例:

with n as (
      select level n
      from dual connect by level <= 20
     ),
     t as (
      select 1 as id, to_date('01/01/2000 4', 'mm/dd/yyyy hh') as StartDate, to_date('01/03/2000 6', 'mm/dd/yyyy hh') as EndDate from dual union all
      select 2 as id, to_date('01/04/2000 8', 'mm/dd/yyyy hh') as StartDate, to_date('01/04/2000 12', 'mm/dd/yyyy hh') as EndDate from dual union all
      select 3 as id, to_date('01/05/2000', 'mm/dd/yyyy') as StartDate, to_date('01/06/2000', 'mm/dd/yyyy') as EndDate from dual
     )
select t.id,
       (case when n = 1 then StartDate
             else trunc(StartDate + n - 1)
        end) as StartDate,
       (case when trunc(StartDate + n - 1) = trunc(enddate)
             then enddate
             else trunc(StartDate + n)
        end)
from t join
     n
     on StartDate + n - 1 <= EndDate
order by id, StartDate

此处它位于SQLFiddle上.

Here it is on SQLFiddle.

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