Oracle-如何创建具有ID的自动递增唯一键的表 [英] Oracle - How do I create a table that has an autoincrementing unique key for the ID

问题描述

这是我第一次使用oracle SQL，但在创建具有唯一键的表时遇到了问题.

This is the first time that I've use oracle SQL and I'm having a problem creating tables with a unique key.

我不明白为什么此自动递增ID无法正常工作:

I don't understand why this auto-incrementing id is not working:

ID BIGINT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY

我的下一个问题是为什么我的每条陈述都出现错误:

The next question I have is why I am getting an error in each of my statements:

ORA-00922: missing or invalid option

这是我的代码:

--
-- Sequence for aout incrment
--
CREATE SEQUENCE IF NOT EXISTS AUTO_INC_SEQ
START WITH 1
INCREMENT BY 1;

--
-- Table Person
--
CREATE TABLE IF NOT EXISTS FITNESS_PERSON
(
ID NUMBER NOT NULL PRIMARY KEY,
FIRST_NAME VARCHAR NOT NULL,
LAST_NAME VARCHAR NOT NULL,
NICK_NAME VARCHAR NOT NULL,
DATE_BIRTH DATE NOT NULL,
PASSWORD VARCHAR NOT NULL,
CONSTRAINT UNIQUE(NICK_NAME)
);

--
-- Table BMR
--
CREATE TABLE IF NOT EXISTS FITNESS_BMR
(
ID NUMBER NOT NULL PRIMARY KEY,
VALUE FLOAT NOT NULL,
VALUE_DATE DATE NOT NULL
);

--
-- M:N for BMR and Person
--
CREATE TABLE IF NOT EXISTS FITNESS_BMR_PERSON
(
BMR_ID NUMBER NOT NULL,
PERSON_ID NUMBER NOT NULL,
FOREIGN KEY(BMR_ID) REFERENCES FITNESS_BMR(ID),
FOREIGN KEY(PERSON_ID) REFERENCES FITNESS_PERSON(ID),
CONSTRAINT BMR_PER PRIMARY KEY(BMR_ID, PERSON_ID)
);

执行此操作的正确方法是什么(创建表并使用唯一的自动递增键).

What's the right way to do this (create a table and with an auto-incrementing key that is unique).

推荐答案

您可以使用表，序列生成唯一ID值和触发器.

You can use a table, a sequence to generate unique ID values and a trigger.

例如:

表格:

CREATE Table FITNESS_BMR
(
ID NUMBER NOT NULL PRIMARY KEY,
VALUE FLOAT NOT NULL,
VALUE_DATE DATE NOT NULL
);

序列:create sequence t1_seq start with 1 increment by 1 nomaxvalue;

触发器:

CREATE OR REPLACE TRIGGER test_trigger
BEFORE INSERT
ON FITNESS_BMR
REFERENCING NEW AS NEW
FOR EACH ROW
BEGIN
SELECT t1_seq.nextval INTO :NEW.ID FROM dual;
END;
/   

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