如何在没有类的情况下覆盖当前脚本的魔术方法? [英] How to override a magic method for the current script without a class?

问题描述

如何为当前脚本覆盖魔术方法?

How to override a magic method for the current script?

def __setattr__(name, value):
    __dict__[name] = value
    print("asd")
    if name == 'b':
        print(__dict__[name])


if __name__ == '__main__':
    a = 3
    b = 4
    b = 5

例如，在上面，我希望对b的赋值可以调用__setattr__，但不会.我想念什么?

In above, for example, I expect assignments to b to call __setattr__ but they don't. What am I missing?

推荐答案

__setattr__仅 适用于形式为a.b = c的赋值，该形式转换为type(a).__setattr__(b, c).简单的名称分配是语言本身的基本操作，没有任何魔术方法可以实现.

__setattr__ only applies to assignments of the form a.b = c, which translates to type(a).__setattr__(b, c). Simple name assignments are a fundamental operation of the language itself, not implemented by any magic method.

您只是在定义一个名为__setattr__的模块级函数，而不是任何特定类的魔术方法.

You are just defining a module level function named __setattr__, not a magic method of any particular class.

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