jQuery分页仅显示上一个和下一个 [英] Jquery Pagination only show prev and next
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问题描述
我正在使用Jquery对页面上的一些div分页.目前分页显示为:
I am using Jquery to paginate some divs on my page. At the moment the pagination shows as:
上一个1 2 3 4 5 6 7 8 9下一个
prev 1 2 3 4 5 6 7 8 9 next
如何对其进行自定义,使其仅显示上一个和下一个按钮:上一页下一页?????
How can I customize it to only show a previous and next button: prev next ?????
代码:
// JavaScript Document
$(document).ready(function(){
//how much items per page to show
var show_per_page = 5;
//getting the amount of elements inside content div
var number_of_items = $('#paginationcontent').children().size();
//calculate the number of pages we are going to have
var number_of_pages = Math.ceil(number_of_items/show_per_page);
//set the value of our hidden input fields
$('#current_page').val(0);
$('#show_per_page').val(show_per_page);
//now when we got all we need for the navigation let's make it '
/*
what are we going to have in the navigation?
- link to previous page
- links to specific pages
- link to next page
*/
var navigation_html = '<a class="previous_link" href="javascript:previous();">Prev</a>';
var current_link = 0;
while(number_of_pages > current_link){
navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';
current_link++;
}
navigation_html += '<a class="next_link" href="javascript:next();">Next</a>';
$('#page_navigation').html(navigation_html);
//add active_page class to the first page link
$('#page_navigation .page_link:first').addClass('active_page');
//hide all the elements inside content div
$('#paginationcontent').children().css('display', 'none');
//and show the first n (show_per_page) elements
$('#paginationcontent').children().slice(0, show_per_page).css('display', 'block');
});
function previous(){
new_page = parseInt($('#current_page').val()) - 1;
//if there is an item before the current active link run the function
if($('.active_page').prev('.page_link').length==true){
go_to_page(new_page);
}
}
function next(){
new_page = parseInt($('#current_page').val()) + 1;
//if there is an item after the current active link run the function
if($('.active_page').next('.page_link').length==true){
go_to_page(new_page);
}
}
function go_to_page(page_num){
//get the number of items shown per page
var show_per_page = parseInt($('#show_per_page').val());
//get the element number where to start the slice from
start_from = page_num * show_per_page;
//get the element number where to end the slice
end_on = start_from + show_per_page;
//hide all children elements of content div, get specific items and show them
$('#paginationcontent').children().css('display', 'none').slice(start_from, end_on).css('display', 'block');
/*get the page link that has longdesc attribute of the current page and add active_page class to it
and remove that class from previously active page link*/
$('.page_link[longdesc=' + page_num +']').addClass('active_page').siblings('.active_page').removeClass('active_page');
//update the current page input field
$('#current_page').val(page_num);
}
推荐答案
删除
while(number_of_pages > current_link){
navigation_html += '<a class="page_link" href="javascript:go_to_page(' + current_link +')" longdesc="' + current_link +'">'+ (current_link + 1) +'</a>';
current_link++;
}
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