用分隔符pandas python拆分列 [英] splitting a column by delimiter pandas python

问题描述

我有一些样本数据:

import pandas as pd

df = {'ID': [3009, 129,119,120,121,122,130,3014,266,849,174,844 ],
  'V': ['IGHV7-B*01','IGHV7-B*01','IGHV6-A*01','GHV6-A*01','IGHV6-A*01','IGHV6-A*01','IGHV4-L*03','IGHV4-L*03','IGHV5-A*01','IGHV5-A*04','IGHV6-A*02','IGHV6-A*02'],
  'Prob': [1,1,0.8,0.8056,0.9,0.805 ,1,1,0.997,0.401,1,1]}


df = pd.DataFrame(df)

看起来像

df    

Out[25]: 
      ID    Prob           V
0    3009  1.0000  IGHV7-B*01
1     129  1.0000  IGHV7-B*01
2     119  0.8000  IGHV6-A*01
3     120  0.8056  IGHV6-A*01
4     121  0.9000  IGHV6-A*01
5     122  0.8050  IGHV6-A*01
6     130  1.0000  IGHV4-L*03
7    3014  1.0000  IGHV4-L*03
8     266  0.9970  IGHV5-A*01
9     849  0.4010  IGHV5-A*04
10    174  1.0000  IGHV6-A*02
11    844  1.0000  IGHV6-A*02

我想用'-'分隔符分隔'V'列，并将其移至名为'allele'的另一列

    Out[25]: 
      ID    Prob      V    allele
0    3009  1.0000  IGHV7    B*01
1     129  1.0000  IGHV7    B*01
2     119  0.8000  IGHV6    A*01
3     120  0.8056  IGHV6    A*01
4     121  0.9000  IGHV6    A*01
5     122  0.8050  IGHV6    A*01
6     130  1.0000  IGHV4    L*03
7    3014  1.0000  IGHV4    L*03
8     266  0.9970  IGHV5    A*01
9     849  0.4010  IGHV5    A*04
10    174  1.0000  IGHV6    A*02
11    844  1.0000  IGHV6    A*02

到目前为止，我尝试过的代码不完整，无法正常工作:

the code i have tried so far is incomplete and didn't work:

df1 = pd.DataFrame()
df1[['V']] = pd.DataFrame([ x.split('-') for x in df['V'].tolist() ])

或

df.add(Series, axis='columns', level = None, fill_value = None)
newdata = df.DataFrame({'V':df['V'].iloc[::2].values, 'Allele': df['V'].iloc[1::2].values})

推荐答案

使用矢量化的 查看全文