按元素检查是否存在字符串 [英] check element-wise for existence of string

问题描述

我正在寻找一种方法来检查是否可以在另一个字符串中找到一个字符串. str.contains仅采用固定的字符串模式作为参数，我希望在两个字符串列之间进行逐元素比较.

I'm looking for a way to check whether one string can be found in another string. str.contains only takes a fixed string pattern as argument, I'd rather like to have an element-wise comparison between two string columns.

import pandas as pd

df = pd.DataFrame({'long': ['sometext', 'someothertext', 'evenmoretext'],
               'short': ['some', 'other', 'stuff']})


# This fails:
df['short_in_long'] = df['long'].str.contains(df['short'])

预期输出:

[True, True, False]

推荐答案

对zip使用列表理解:

df['short_in_long'] = [b in a for a, b in zip(df['long'], df['short'])]

print (df)
            long  short  short_in_long
0       sometext   some           True
1  someothertext  other           True
2   evenmoretext  stuff          False

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