在多级数据框中重新索引第二级 [英] Reindex 2nd level in multi-level dataframe
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问题描述
我需要重新索引熊猫数据框的第二级,以便第二级成为每个第一级索引的列表np.arange(N)
.我尝试遵循此,但不幸的是,它只能创建具有相同数量的索引以前存在的行.我想要的是为每个新索引插入新行(带有nan值).
I need to reindex the 2nd level of a pandas dataframe, so that the 2nd level becomes a list np.arange(N)
for each 1st level index. I tried to follow this, but unfortunately it only creates an index with as many rows as previously existing. What I want is that for each new index new rows are inserted (with nan values).
In [79]:
df = pd.DataFrame({
'first': ['one', 'one', 'one', 'two', 'two', 'three'],
'second': [0, 1, 2, 0, 1, 1],
'value': [1, 2, 3, 4, 5, 6]
})
print df
first second value
0 one 0 1
1 one 1 2
2 one 2 3
3 two 0 4
4 two 1 5
5 three 1 6
In [80]:
df['second'] = df.reset_index().groupby(['first']).cumcount()
print df
first second value
0 one 0 1
1 one 1 2
2 one 2 3
3 two 0 4
4 two 1 5
5 three 0 6
我想要的结果是:
first second value
0 one 0 1
1 one 1 2
2 one 2 3
3 two 0 4
4 two 1 5
4 two 2 nan
5 three 0 6
5 three 1 nan
5 three 2 nan
推荐答案
我认为您可以先将列first
和second
设置为多级索引,然后再设置reindex
.
I think you can first set columns first
and second
as multi-level index, and then reindex
.
# your data
# ==========================
df = pd.DataFrame({
'first': ['one', 'one', 'one', 'two', 'two', 'three'],
'second': [0, 1, 2, 0, 1, 1],
'value': [1, 2, 3, 4, 5, 6]
})
df
first second value
0 one 0 1
1 one 1 2
2 one 2 3
3 two 0 4
4 two 1 5
5 three 1 6
# processing
# ============================
multi_index = pd.MultiIndex.from_product([df['first'].unique(), np.arange(3)], names=['first', 'second'])
df.set_index(['first', 'second']).reindex(multi_index).reset_index()
first second value
0 one 0 1
1 one 1 2
2 one 2 3
3 two 0 4
4 two 1 5
5 two 2 NaN
6 three 0 NaN
7 three 1 6
8 three 2 NaN
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