C ++，命令行，参数 [英] C++, command line, parameters

问题描述

我正在从命令行启动c ++程序:

I am starting my c++ program from command line:

program input_file1 input_file2 output_file

其中

int main( int argc, char *argv[] )
{
    short indicator= 3;
    char input_file1[4096], input_file2[4096], output_file[4096];
    char *p_file = NULL;
    while ( --argc > 0 ) {
        switch (--indicator) {
          case 2:
            p_file = output_file;
            break;
          case 1:
            p_file = input_file2;
            break;
          case 0:
            p_file = input_file1;
            break;
        }

        for (char *argument = argv[argc]; ; ++argument) {
            if (*argument == '\0')
                break;
            else
                *p_file++ = *argument;
        }

        *p_file = '\0'; 
    }

    std::cout << input_file1 << '\n';
    std::cout << input_file2 << '\n';
    std::cout << output_file << '\n';
}

但是带有真实的论点

program D:\\data\\file1.txt D:\\data\\file2.txt D:\\data\\file3.txt

在文件名中仅存储第一个字母D ...

in names of the files only the first letter D is stored...

Output:
D
D
D

感谢您的帮助...

推荐答案

好的，所以这是简短的版本:

Ok, so here is the short version:

int main(int argc, char *argv[]) {
    if (argc != 2) {
        std::cout << "This program requires 1 argument!" << std::endl;
        return 1;
    }
    std::string input_file(argv[1]);
    std::cout << input_file << std::endl;
}

您应该可以从这里拿走它.

You should be able to take it from here.

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