使用数组和函数来打印C中的前n个元素[就像sort(a + m，a + n)] [英] Use of array and a function to print first n elements in C [as like as sort(a+m, a+n)]

问题描述

问题:我想编写一个函数，以将数组从mth元素打印到第n个元素，其中m <= n，如果a是数组，则函数调用应类似于print(a + m，a + n ).现在，在这种情况下，用户定义的功能应该是什么?

#include <stdio.h>
#include <iostream>

using namespace std;
/* It may be ok or not. If not then what program should write? */
void print(int a[], int n)
{
    for(int i=0;; ++i){
        if(a[i] == a[n]) break;
        printf("%d ",a[i]);
    }
}

int main()
{
    int a[6] = {1,3,5,6,8,2};
    /*We can use to sort this array of 1st n elements*/
    sort(a,a+n);
    /*if we want to use c function to sort this array 'a' for 1st 4 elements then we write*/
    sort(a,a+4);

   /*But if we want use to print 1st n elements than what should user defined function looks like?*/

    print(a,a+3); //for this function to print 1st 3 elements what should write user defined         function

    return 0;
}

推荐答案

您可以将指针用于这种格式

You can use pointers for such format

void print (int * begin, int * end){
  while(begin != end){
    printf("%d", *begin);
    begin++;
  }
}

这篇关于使用数组和函数来打印C中的前n个元素[就像sort(a + m，a + n)]的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！