Powershell:如何远程传递带有invoke-command和-filepath的参数? [英] Powershell: How to pass parameter with invoke-command and -filepath remotely?

问题描述

因此，我发现了很多与此类似的主题，但是找不到与我的问题相关的任何东西.

so there's a lot of similar topics to this I've found, but I can't find anything that correlates with my issue.

invoke-command -computername $serverLocation -Credential $cred -filepath "C:\path\script2.ps1" -ArgumentList $configPath

我正在为存储在我的本地计算机上的脚本调用，以在另一台服务器上运行.除了传递"configPath"变量外，其他所有操作均按预期进行.这就是我启动脚本的方式-

I am calling a for a script that is stored on my local machine to run on another server. Everything works as intended except for passing the "configPath" variable. This is how I initiate the script -

. .\script1.ps1 -serverLocation 'serverNameHere' -username 'userNameHere' -configPath 'configPathHere' 

它正确地捕获了我传递给第一个脚本的所有其他参数.它只是不会将configPath传递给文件路径"中的第二个脚本.

It correctly grabs all the other parameters I pass into the first script. It just won't pass the configPath to the second script in the 'filepath'.

如何获取此参数?非常感谢.

How can I get this parameter to pass through? Thanks so much.

推荐答案

在script2.ps1中，您应该定义一个接受参数的param()块，然后您可以使用提供的任何名称来引用它.如果您不想使用param()块，则可以使用$args[0].

In script2.ps1, you should define a param() block that accepts the parameter, and then you can refer to it by whatever name you give it. If you don't want to use a param() block then using $args[0] should work.

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