快速子类PFUser [英] Subclass PFUser in swift

问题描述

我想快速将PFUser对象子类化. 我也想声明自己的变量.此时，有关子类的Parse文档尚未涵盖PFUser.

I wanna subclass the PFUser object in swift. I also want to declare my own variables. The Parse documentation on subclassing do not cover PFUser at this point.

解析有关子类PFObject的文档:

Parse documentation on subclassing PFObject:

class Armor : PFObject, PFSubclassing {
    class func load() {
       self.registerSubclass()
    }
    class func parseClassName() -> String! {
       return "Armor"
    }
}

推荐答案

BridgingHeader.h:

#import <Parse/Parse.h>
#import <Parse/PFObject+Subclass.h>

User.swift:

import Foundation

class User : PFUser, PFSubclassing {

override class func load() {
    self.registerSubclass()
}

//My variables
dynamic var firstname: String
dynamic var lastname: String

}

在为PFUser子类化时，请勿包含此代码段:

class func parseClassName() -> String! {
    return "User"
}

这篇关于快速子类PFUser的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！