PYTHON-捕获大括号内的内容 [英] PYTHON - Capture contents inside curly braces

问题描述

因此，作为我的应用程序的一部分，我需要它从文本文件中读取数据，并在大括号之间获取元素.

So, as part of my application, i need it to read data from a text file, and get elements between curly brackets.

例如:

服务器_1 {

Server_1 {

/directory1/directory2

/directory1 /directory2

}

服务器_2 {

/directory1

/directory1

/directory2

/directory2

}

然后类似，如果是Server == Server_1，则打印目录.

Then something like, if Server == Server_1, print the directories.

亲切的问候，

迈克尔

推荐答案

您可以尝试以下操作:

\{(.*?)\}

说明

1. \{ matches the character { literally (case sensitive)
2. (.*?) 1st Capturing Group
3. .*?匹配任何字符
4. *?量词-匹配零次至无限次，次数尽可能少，根据需要扩展(延迟)
5. \}从字面上匹配字符}(区分大小写)

1. \{ matches the character { literally (case sensitive)
2. (.*?) 1st Capturing Group
3. .*? matches any character
4. *? Quantifier — Matches between zero and unlimited times, as few times as possible, expanding as needed (lazy)
5. \} matches the character } literally (case sensitive)

示例代码以提取大括号内的内容:

Sample Code to extract content inside curly bracket:

 import re

regex = r"\{(.*?)\}"

test_str = ("Server_1 {\n"
    "/directory1 /directory2\n\n"
    "}\n"
    "Server_2 {\n\n"
    "/directory1\n\n"
    "/directory2\n\n"
    "}")

matches = re.finditer(regex, test_str, re.MULTILINE | re.DOTALL)

for matchNum, match in enumerate(matches):
    for groupNum in range(0, len(match.groups())):
        print (match.group(1))

在此处运行代码

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