如何解析json以获取数组中特定键的所有值? [英] How to parse json to get all values of a specific key within an array?

问题描述

我在尝试使用python从json数组中的特定键中获取值列表时遇到麻烦.使用下面的JSON示例，我试图创建一个仅包含name键值的列表. 原始JSON:

I'm having trouble trying to get a list of values from a specific key inside an json array using python. Using the JSON example below, I am trying to create a list which consists only the values of the name key. Original JSON:

[
    {
        "id": 1,
        "name": "Bulbasaur",
        "type": [
            "grass",
            "poison"
        ]
    },
    {
        "id": 2,
        "name": "Ivysaur",
        "type": [
            "grass",
            "poison"
        ]
    }
]

预期:

["Bulbasaur", "Ivysaur"]

下面是我的方法的代码:

Below is the code of my approach:

import json
try:
    with open("./simple.json", 'r') as f:
        contents = json.load(f)
except Exception as e:
    print(e)

print(contents[:]["name"])

我正在尝试一种不需要循环每个索引并附加它们的方法，就像上面的代码一样.使用python的json库可以实现这种方法吗?

I'm trying to go to an approach where i don't need to loop every single index and append them, something like the code above. Is this approach possible using python' json library?

推荐答案

您不能执行contents[:]["name"]，因为contents是一个包含整数索引的列表，并且您不能使用字符串.

You cannot do contents[:]["name"] since contents is a list is a dictionary with integer indexes, and you cannot access an element from it using a string name.

要解决此问题，您需要遍历列表并为每个item

To fix that, you would want to iterate over the list and get the value for key name for each item

import json
contents = []

try:
    with open("./simple.json", 'r') as f:
        contents = json.load(f)
except Exception as e:
    print(e)


li = [item.get('name') for item in contents]
print(li)

输出将是

['Bulbasaur', 'Ivysaur']

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