XSLT解析存储在属性中的转义HTML，并将该属性的内容转换为元素的内容 [英] XSLT parse escaped HTML stored in an attribute and convert that attribute's content into element's content

问题描述

我坚持我认为应该做的简单的事情.我一直在环顾四周，但是没有找到解决方案.希望你能帮助我.

I'm stuck on what I think should be simple thing to do. I've been looking around, but didn't find the solution. Hope you will help me.

我所拥有的是一个XML元素，其属性包含转义的HTML元素:

What I have is an XML element with an attribute that contains escaped HTML elements:

<Booking>    
  <BookingComments Type="RAM" comment="RAM name fred&lt;br/&gt;Tel [phone]&lt;br/&gt;Email [e-mail]" />
</Booking>

我需要获取的是将@comment属性中的HTML元素和内容解析为

元素的内容，如下所示:

What I need to get is parsed HTML elements and content from the @comment attribute to be a content of

element as follows:

<p>
  RAM name fred<br/>Tel [phone]<br/>Email [e-mail]
<p>

这是我的XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" exclude-result-prefixes="xs fn" version="1.0">


<xsl:output method="html" doctype-public="-//W3C//DTD HTML 4.01 Transitional//EN" 
    doctype-system="http://www.w3.org/TR/html4/loose.dtd" encoding="UTF-8" indent="yes" />

 <xsl:template name="some-template">
   <p>Some text</p>
   <p>
      <xsl:copy-of
        select="/Booking/BookingComments[lower-case(@Type)='ram'][1]/@comment"/>
   </p>     
 </xsl:template>
</xsl:stylesheet>

我已经阅读到copy-of是将转义的HTML元素还原回适当元素的好方法.在这种特定情况下，因为它最初是属性，所以copy-of也会将其转换为属性.所以我得到:

I've read that copy-of is a good way to restore escaped HTML elements back to proper elements. In this specific case, because it's initially an attribute the copy-of translates it into attribute as well. So I get:

<p comment="RAM name fred<br/&gt;Tel [phone]<br/&gt;Email [e-mail]"></p>

那不是我想要的.

如果我使用apply-templates而不是copy-of，例如:

If I use apply-templates instead of copy-of, as in:

<p>
  <xsl:apply-templates select="/Booking/BookingComments[lower-case(@Type)='ram'[1]/@comment"/>
</p>

我只是以文本形式获取p的内容，而不是还原的HTML元素.

I get p's content simply as text, not restored HTML elements.

<p>RAM name fred&lt;br/&gt;Tel [phone]&lt;br/&gt;Email [e-mail]</p>

我确定我错过了一些过时的东西.我真的很感谢您的帮助和提示！

I'm sure I'm missing something obvous. I would really appreciate any help and tips!

推荐答案

我建议使用专用模板:

<!-- check if lower-casing @Type is really necessary -->
<xsl:template name="BookingComments[lower-case(@Type)='ram']/@comment">
  <p>
    <xsl:value-of select="." disable-output-escaping="yes" />
  </p>     
</xsl:template>

这样，您可以简单地将模板应用于属性.请注意，禁用输出转义可能会生成格式错误的输出.

This way you could simply apply templates to the attribute. Note that disabling output escaping has the potential to generate ill-formed output.

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