将命令行语句解析为令牌列表 [英] Parsing command line statements as a list of tokens

问题描述

#include <stdio.h>
#include <string.h> /* needed for strtok */
#include <unistd.h>
#include <stdlib.h>

int main(int argc, char **argv) {
        char text[10000];
    fgets(text, sizeof(text), stdin);
    char *t;
    int i;

    t = strtok(text, "\"\'| ");
    for (i=0; t != NULL; i++) {
        printf("token %d is \"%s\"\n", i, t);
        t = strtok(NULL, "\"\'| ");
    }
}

这是我试图使其分离标记的代码的一部分

This is part of the code that im trying to make it is supposed to separate tokens

假设输入为'abc' "de f'g" hij| k "lm | no"

输出应为

token 1: "abc"
token 2: "de f'g"
token 3: "hij"
token 4: "|"
token 5: "k"
token 6: "lm | no"

我得到了一些不同的东西，但是无论如何我都可以将其更改为这种格式?

I get something different but close anyway I can change it to this format?

推荐答案

#include <stdio.h>
#include <string.h>

char *getToken(char **sp){
    static const char *sep = " \t\n";
    static char vb[] = "|", vbf;
    char *p, *s;
    if(vbf){
        vbf = 0;
        return vb;
    }
    if (sp == NULL || *sp == NULL || **sp == '\0') return(NULL);
    s = *sp;
    if(*s == '"')
        p = strchr(++s, '"');
    else if(*s == '\'')
        p = strchr(++s, '\'');
    else
        p = s + strcspn(s, "| \t\n");
    if(*p != '\0'){
        if(*p == '|'){
            *vb = vbf = '|';
        }
        *p++ = '\0';
        p += strspn(p, sep);
    }
    *sp = p;
    if(!*s){
        vbf = 0;
        return vb;
    }
    return s;
}

int main(int argc, char **argv) {
    char text[10000];
    fgets(text, sizeof(text), stdin);
    char *t, *p = text;
    int i;

    t = getToken(&p);
    for (i=1; t != NULL; i++) {
        printf("token %d is \"%s\"\n", i, t);
        t = getToken(&p);
    }
    return 0;
}

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