xml列表的Python函数 [英] Python function for xml list
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问题描述
我已经解析了如下所示的XML文件.也许我只是复印不好，但是没关系，所以，这里是:
I have parsed XML file looking like this. Maybe I just didn't copy well,but it's ok, so, here it is:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE raml SYSTEM 'raml20.dtd'>
<raml version="2.0" xmlns="raml20.xsd">
<cmData type="actual">
<managedObject class="LN" distName="PTR" id="2425">
<p name="aak">220</p>
<p name="orp">05</p>
<p name="name">Portro</p>
<p name="optres">false</p>
<p name="optblu">false</p>
<p name="aoptdet">false</p>
<p name="advcell">false</p>
<list name="sibList">
<item>
<p name="sibcity">177</p>
<p name="sibrep">2</p>
</item>
<item>
<p name="sibcity">177</p>
<p name="sibrep">1</p>
</item>
</list>
</managedObject>
<managedObject class="LN" distName="KRNS" id="93886">
<p name="aak">150</p>
<p name="orp">05</p>
<p name="name">Portro</p>
<p name="optres">false</p>
<p name="optblu">tru</p>
<p name="aoptdet">false</p>
<p name="advcell">true</p>
<list name="sibList">
<item>
<p name="sibcity">177</p>
<p name="sibrep">1</p>
</item>
<item>
<p name="sibcity">180</p>
<p name="sibrep">2</p>
</item>
</list>
</managedObject>
....
<managedObject>
...
</managedObject>
...
</cmData>
</raml>
我需要遍历所有"managedObject"，并将第一个managedObject中的每个参数(p名称)与另一个managedObjects中的参数(aak，orp等)进行比较，并获得不同参数及其值的输出(如果有)参数没有不同的值，什么也不做.我编写了用于比较的代码，但是我不知道如何遍历列表(名为"sibList")和比较参数.我写了这个函数，其中键是"p name"，值是"p name"的值:
I need to go through all "managedObject" and compare every parameter(p name) from first managedObject with parameters (aak, orp, etc.) from another managedObjects, and get output of different parameters and values of them, if there is no different values of parameters, do nothing. I wrote code for comparasion, but I don't know how to go through list (it's named "sibList") and compare parameters. I wrote this function, where key is "p name" and value is value of "p name":
temp = []
for i in temp_ln:
for j, k in zip(i.getchildren(), i):
temp.append([i.get('distName'), j.get('name'), j.text])
tempdict = {}
for i in temp_ln:
td = {}
for j in i.getchildren():
td.update({j.get('name'): j.text})
tempdict.update({i.get('distName'): td})
elements_list = {}
if j.get('name') == 'sibList':
for item in j.getchildren():
for w in item.getchildren():
elements_list.update({ w.get('name'): w.text})
main_dif = {}
for key, value in tempdict.iteritems():
dif_k = {}
for k, v in value.iteritems():
try:
a = ref[k]
except:
a = None
if v != a:
if k == 'name':
pass
else:
dif_k.update({k:(v, a)})
main_dif.update({key:dif_k})
推荐答案
这里是一种解析XML文件，将每个ManagedObject与所有其他托管对象进行比较，并打印出结果diff对象的解决方案.
Here is a solution that parse the XML file, and compares each managedObject with all others, and print out the resulting diff object.
import json
from xml.etree import ElementTree
tree = ElementTree.parse('raml20.xml')
ns = {'ns': 'raml20.xsd'}
nsP, nsList, nsItem = ('{%s}%s' % (ns['ns'], i) for i in ('p', 'list', 'item'))
def pkv(o):
"""Return dict with name:text of p elements"""
return {k.attrib['name']: k.text for k in o.iter(nsP)}
def parse(tree):
root = tree.getroot()
objs = {}
for mo in root.findall('./ns:cmData/ns:managedObject', ns):
obj = pkv(mo)
for i in mo.iter(nsList):
obj[i.attrib['name']] = [pkv(j) for j in i.iter(nsItem)]
objs[mo.attrib['distName']] = obj
return objs
def diff_dicts(d1, d2, ignore_keys=set()):
"""Return dict with differences between the dicts provided as arguments"""
k1 = set(d1.keys())
k2 = set(d2.keys())
diff = {}
diff.update(
{i: (d1[i], d2[i]) for i in (k1 & k2) - ignore_keys if d1[i] != d2[i]})
diff.update({i: (d1.get(i), d2.get(i)) for i in (k1 ^ k2) - ignore_keys})
return diff
def diff_lists(l1, l2):
"""Return dict with differences between lists of dicts provided as arguments"""
diff = {}
# note: assumes that lists are of same length
for i, (d1, d2) in enumerate(zip(l1, l2)):
d = diff_dicts(d1, d2)
if d:
diff[i] = d
return diff
def diff_objects(o1, o2):
"""Return dict with differences between two objects (dicts) provided as arguments"""
listkeys = set(
i for o in (o1, o2) for i in o if isinstance(o.get(i), list))
diff = diff_dicts(o1, o2, listkeys)
for i in listkeys:
if i in o1 and i in o2:
diff.update({i: diff_lists(o1[i], o2[i])})
else:
diff.update({i: (o1.get(i), o2.get(i))})
return diff
def compare_objects(objs):
diffs = []
keys = list(objs)
for k1, k2 in zip(keys[:-1], keys[1:]):
o1, o2 = objs[k1], objs[k2]
diff = diff_objects(o1, o2)
if diff:
diffs.append((k1, k2, diff))
return diffs
res = compare_objects(parse(tree))
print(json.dumps(res, indent=2))
我已经使用以下raml20.xml文件进行了测试:
I've tested with the following raml20.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE raml SYSTEM 'raml20.dtd'>
<raml version="2.0" xmlns="raml20.xsd">
<cmData type="actual">
<managedObject class="LN" distName="PTR" id="2425">
<p name="aak">220</p>
<p name="orp">05</p>
<p name="name">Portro</p>
<p name="optres">false</p>
<p name="optblu">false</p>
<p name="aoptdet">false</p>
<p name="advcell">false</p>
<list name="sibList">
<item>
<p name="sibcity">177</p>
<p name="sibrep">2</p>
</item>
<item>
<p name="sibcity">177</p>
<p name="sibrep">1</p>
</item>
</list>
</managedObject>
<managedObject class="LN" distName="KRNS" id="93886">
<p name="aak">150</p>
<p name="orp">05</p>
<p name="name">Portro</p>
<p name="optres">false</p>
<p name="optblu">tru</p>
<p name="aoptdet">false</p>
<p name="advcell">true</p>
<list name="sibList">
<item>
<p name="sibcity">177</p>
<p name="sibrep">1</p>
</item>
<item>
<p name="sibcity">180</p>
<p name="sibrep">2</p>
</item>
</list>
</managedObject>
</cmData>
</raml>
生成的diff对象为:
The resulting diff object is:
[
[
"PTR",
"KRNS",
{
"advcell": [
"false",
"true"
],
"optblu": [
"false",
"tru"
],
"sibcity": [
"177",
"180"
],
"aak": [
"220",
"150"
],
"sibrep": [
"1",
"2"
],
"sibList": {
"0": {
"sibrep": [
"2",
"1"
]
},
"1": {
"sibcity": [
"177",
"180"
],
"sibrep": [
"1",
"2"
]
}
}
}
]
]
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