用向量的值替换XML文件中的值 [英] Replace values in XML file with values of a vector

问题描述

我有一个XML文件，我需要使用Python代码用向量v=[7,8,9]中的值替换类型"之后的值.我需要代码来识别单词"type"，然后在下一行中更改参数的值.值2应替换为v[0]，3应替换为v[1]，依此类推.有没有办法用ElementTree或readlines做到这一点?

I have an XML file and I need to replace the value that comes right after "type" with a value from a vector v=[7,8,9] using a Python code. I need the code to recognize the word "type" and then change the value of the parameter in the following line. The value 2 should be replaced by v[0], 3 by v[1] and so on. Is there a way to do this with ElementTree or with readlines?

<Model>
    <Function>
      <param>x</param>
      <param>type</param>
      <param>2</param>
      <param>5</param>
    </Function>
    <Function>
      <param>y</param>
      <param>type</param>
      <param>3</param>
      <param>2</param>
    </Function>
    <Function>
      <param>z</param>
      <param>type</param>
      <param>7</param>
      <param>9</param>
     </Function>
</Model>

推荐答案

我们可以使用模块xml.etree.ElementTree更改值. 在代码中，child表示Function标记，child [x]表示Function标记中的x ^th 元素.通过使用text属性，我们可以访问元素的值.

we can change values using the module xml.etree.ElementTree. In code child represents Function tag and child[x] represents x^th element in the Function tag.By using text attribute we can access values of elements.

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')
root = tree.getroot()
v = [7, 8, 9]
for child in root:
  child[2].text = str(v.pop(0))

tree.write('output.xml')

另一种方法:

我们还可以通过比较元素来解决，如果元素文本等于type，则我们更新其旁边的值.

we can also solve by comparing the elements, if element text is equal to type then we update the value next to it.

elements = root.findall('Function/param')

for i in range(len(elements)):
  if elements[i].text == 'type':
    elements[i + 1].text = str(v.pop(0))

tree.write('output.xml')

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