解析Apache通用日志格式的日志文件 [英] Parse apache common log format log files

问题描述

我正在尝试从一个常见的日志格式日志文件中获取三条信息.日志文件的条目为:

I'm trying to take three pieces of information from a common log format log file. An entry of the log file would be:

65.54.188.137 - - [03/Oct/2007:02:20:22 -0400] "GET /~longa/statistics/code/xlispstat/smoothers/spline/ HTTP/2.0" 301 2633

，然后，我想将IP，URL和状态代码的出现次数存储在哈希中.我认为他们每个人都必须独立存在.即使您能指出正确的方向，也可以提供任何帮助.

and from that, I want to store the number of occurrences of the IP, the URLs, and the status codes in a hash. I figured they each have to be in their own. Any help would be appreciated, even if you can just point me in the right direction.

推荐答案

您可以使用正则表达式从日志条目中读取信息.像这样:

You can read the information from the log entries with a regular expression. Something like this:

lines.each do |line|
  matches = /^(\S+).*GET\s(.*)\sHTTP\S*\s(\d+)/.match(line)
  ip = matches[1]
  url = matches[2]
  status = matches[3]
do

然后，您可以将该信息放入哈希中，并按自己的意愿进行处理.

Then you can put this information into a hash and process it how you like.

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