正则表达式检测c函数体的开始 [英] Regex to detect begining of the c function body

问题描述

我正在研究一个perl脚本，该脚本从c源文件打印所需的函数体.我已经写了一个正则表达式来作为函数体的开头

I working on a perl script that prints the required function body from the c source file. i have written a regex to get to the start of the function body as

(/(void|int)\s*($function_name)\s*\(.*?\)\s*{/s

但这仅适用于返回void或int(基本类型)的函数 我如何更改此正则表达式以处理用户定义的数据类型(结构或指针)

but this works only for functions returning void or int(basic types) how can i change this regex to handle user defined datatypes (struct or pointers)

推荐答案

尝试此操作(未经测试！)，尽管它确实希望函数从行的开头开始:

Try this one (untested!), although it does expect the function to start at the beginning of a line :

/
^                            # Start of line
\s*(?:struct\s+)[a-z0-9_]+   # return type
\s*\**                       # return type can be a pointer
\s*([a-z0-9_]+)              # Function name
\s*\(                        # Opening parenthesis
(
    (?:struct\s+)            # Maybe we accept a struct?
    \s*[a-z0-9_]+\**         # Argument type
    \s*(?:[a-z0-9_]+)        # Argument name
    \s*,?                    # Comma to separate the arguments
)*
\s*\)                        # Closing parenthesis
\s*{?                        # Maybe a {
\s*$                         # End of the line
/mi                          # Close our regex and mark as case insensitive

您可以通过删除空格和注释将所有这些压缩为一行.

You can squeeze all of these into a single line by removing the whitespace and comments.

尽管使用正则表达式来解析代码通常很困难，但是这个正则表达式根本不是完美的.

Parsing code with a regex is generally hard though, and this regex is not perfect at all.

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