如何通过CLI程序获取密码? [英] How to get a password with a CLI program?

问题描述

我正在编写Linux CLI程序.我需要从用户那里获得密码，并且显然，我不想将密码回显到控制台.

I am writing a Linux CLI program. I need to get a password from the user and, obviously, I don't want the password to be echoed to the console.

这里有几种解决方案，但是它们都是针对纯C语言的. C命令行密码输入
如何在c中屏蔽密码?
在C语言中使用密码而不使用getpass(3)吗?

There are several solutions available here, but they are all for plain C. C command-line password input
How to mask password in c?
Getting a password in C without using getpass (3)?

如何使用std :: string而不是char []将其用于C ++?

How can those be adapted for C++, using std::string instead of char[]?

最优雅的C ++解决方案是什么?

What would be the most elegant C++ solution?

推荐答案

使用任何普通的C解决方案:

Use any of the plain C solutions:

std::string pass (100);  // size the string at your max password size (minus one)

func_to_get_pass(&pass[0], pass.size());
// function takes a char* and the max size to write (including a null char)

pass.resize(pass.find('\0'));

cout << "Your password is " << pass << ".\n"; // oops! don't show it ;)

这篇关于如何通过CLI程序获取密码?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！