XSL-FO在每个节点之后添加新行 [英] XSL-FO add new line after each node

问题描述

我有一个具有如下结构的XML文件:

I have an XML file with structure like this:

<parent>
    <node>Text 1</node>
    <node>Text 2</node>
    <node>Text 3</node>
    <node>Text 4</node>
    <node>Text 5</node>
</parent>

我想用XSL-FO处理该XML以产生PDF输出.我有以下XSL-FO模板:

I want to process this XML with XSL-FO to produce PDF output. I have following XSL-FO template:

<fo:block>
    <xsl:for-each select="node[position() &lt; last()]">
        <xsl:value-of select="."/>
        <xsl:if test="position() != last()">
            <xsl:text>&#xA;</xsl:text>
        </xsl:if>
    </xsl:for-each>
</fo:block>

这似乎行不通.我得到内联输出，而不是它自己的行中的每个节点.我该如何解决这个问题?

It seems that this doesn't work well. I get output inline, instead of each node in it's own line. How can I resolve this problem?

谢谢！

推荐答案

如果在node元素上进行匹配并为它们创建fo:block，则可以更好地控制事物.您拥有的解决方案是将它们放入内联中，另一个答案可以解决，但对它们的控制较少.

You would have better control of things if you matched on the node element and created an fo:block for them. The solution you have is for putting them inline, the other answer will work but yield less control of them.

如果您希望每个人都换行(这意味着您想要一个新的街区)，则将每个人都放在自己的街区中.

If you want each one in a new line (which means you want a new block area), then put each one is it's own block.

这意味着，您将在XSL中执行以下操作:

Meaning, you would do somewhere in your XSL:

 <xsl:template match="node">
     <fo:block>
         <xsl:apply-templates/>
     </fo:block>
 </xsl:template>

您应该没有理由使用value-of select =.".上面的代码将为您做到这一点，并且如果您将其扩展到在node元素中包含某些内容，那么您的所有内容都将全部设置好.

There should be no reason for you to use value-of select=".". The above will do that for you and if you ever expand to have something inside of the node element, then your are still all set.

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