打开PDF以添加书签/命名目的地? [英] Open PDF to Bookmark/Named Destination?

问题描述

我正在尝试使用python打开指向特定书签的PDF.

I'm trying to open a PDF to a specific bookmark using python.

到目前为止，我已经能够在命令提示符中运行以下命令，并得到我想要的内容( last 是PDF test.pdf中指定目标的名称)

So far, I'm able to run the following command in Command Prompt and get exactly what I want (last is the name of a named destination inside the PDF test.pdf)

"C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe" /A "nameddest=last" "C:\Users\User\Desktop\test.pdf"

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但是当我使用Python并尝试使用子过程模块时，就像这样:

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But when I go to Python and try using the subprocess module like this:

import subprocess
subprocess.call(['"C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe" /A "nameddest=last" "C:\\Users\\User\Desktop\test.pdf"'], shell=True)

我得到文件名，目录名或卷标签语法不正确."在尝试此操作之前，我尝试过一些操作，导致Adobe Reader打开，但是给我一个对话框，显示相同的消息

I get "The filename, directory name, or volume label syntax is incorrect." Something I tried before this caused Adobe Reader to open, but give me a dialog box that had the same message

为什么在python中运行它会发生什么变化?以及我该如何解决?

我正在Windows 8上运行Anaconda 2.1.0，并使用Acrobat 10创建目标.我已经在python上玩了2-3年，但对知识的了解并不比在入门编程班上学一个学期的人多.

I'm running Anaconda 2.1.0 on Windows 8 and using Acrobat 10 to create Destinations. I've played around with python for 2-3 years, but don't know much more than someone with 1 semester of an intro programming class.

推荐答案

已修复:

我是个白痴.

FIXED:

I'm an idiot.

"C:\\Users\\User\Desktop\test.pdf"

是无效的路径，因为\ test.pdf中的\ t被解释为制表符... 将更改添加到\ test.pdf后，它可以工作.

is an invalid path because the \t in \test.pdf is interpretted as a tab... It works after adding changing it to \test.pdf.

以后有相同问题的任何人的代码:

Code for anyone with the same problem later:

import os
import subprocess

page = "3"  
path_to_pdf = os.path.abspath("C:\\Users\\User\Desktop\\test.pdf")
path_to_acrobat = os.path.abspath('C:\Program Files (x86)\Adobe\Reader 11.0\Reader\AcroRd32.exe')


process = subprocess.Popen([path_to_acrobat, '/n', '/A', 'page=' + page, path_to_pdf], shell=False, stdout=subprocess.PIPE)

process.wait()

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