带09前缀的11位电话号码的正则表达式 [英] Reqular expression for 11 digit phone number with 09 prefix

问题描述

我正在尝试编写一个正则表达式来处理以"0"开头，后跟"9"和9位数字(可以是0-9之间的任何数字)的电话号码.

I am trying to write a regular expression to handle phone number which starts with "0" followed by "9" and 9 digits which can be anything within 0-9.

-(BOOL) validateAlphabets: (NSString *)text{      
     NSString *Regex = @"what should be here?!";
     NSPredicate *TestResult = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", Regex];
     return [TestResult evaluateWithObject:text];
}

然后我通过以下方式检查输入验证:

Then I check the input validation by:

if (![self validateAlphabets:self.phoneNumber.text]){
      NSLog(@"Invalid");
   }
else{
      NSLog(@"Valid!");
 }

推荐答案

您可以尝试使用此正则表达式:

You can try to use this Regex:

09[0-9]{9}

REGEX演示

REGEX DEMO

您可以尝试在函数本身中对其进行测试，如下所示:

You can try to test it in your function itself like this:

-(BOOL) validateAlphabets: (NSString *)text{      
     NSString *Regex = @"what should be here?!";
     NSPredicate *TestResult = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", Regex];
     if(TestResult evaluateWithObject: text)
     return true;
     else
     return false;
}

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