如何选择一个句子的前10个单词? [英] How to select first 10 words of a sentence?

问题描述

如何从输出中仅选择前10个字?

How do I, from an output, only select the first 10 words?

推荐答案

implode(' ', array_slice(explode(' ', $sentence), 0, 10));

要增加对其他分词符(如逗号和破折号)的支持，preg_match提供了一种快速方法，不需要拆分字符串:

To add support for other word breaks like commas and dashes, preg_match gives a quick way and doesn't require splitting the string:

function get_words($sentence, $count = 10) {
  preg_match("/(?:\w+(?:\W+|$)){0,$count}/", $sentence, $matches);
  return $matches[0];
}

如Pebbl所述，PHP不能很好地处理UTF-8或Unicode，因此，如果您对此感到担忧，则可以将\w替换为[^\s,\.;\?\!]，将\W替换为[\s,\.;\?\!].

As Pebbl mentions, PHP doesn't handle UTF-8 or Unicode all that well, so if that is a concern then you can replace \w for [^\s,\.;\?\!] and \W for [\s,\.;\?\!].

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