找出哪个类别在另一个类别中称为方法 [英] Find out which class called a method in another class

问题描述

PHP中是否有一种方法可以找出另一个对象中称为哪个方法的对象.

Is there a way in PHP to find out what object called what method in another object.

例如:

class Foo
{
  public function __construct()
  {
    $bar = new Bar();
    $bar->test();
  }
}

class Bar
{
  public function test()
  {
  }
}
$foo = new Foo();

我能找到一种方法是从foo对象中调用测试方法吗?

Would there be a way for me to find out that the test method was called from the foo object?

推荐答案

您可以使用 debug_backtrace ，有点像这样:
顺便说一句，请看一下手册页上的评论:有一些有用的功能和建议；-)

you could use debug_backtrace, a bit like this :
BTW, take a look at the comments on the manual page : there are some useful functions and advices given ;-)

class Foo
{
  public function __construct()
  {
    $bar = new Bar();
    $bar->test();
  }
}

class Bar
{
  public function test()
  {
      $trace = debug_backtrace();
      if (isset($trace[1])) {
          // $trace[0] is ourself
          // $trace[1] is our caller
          // and so on...
          var_dump($trace[1]);

          echo "called by {$trace[1]['class']} :: {$trace[1]['function']}";

      }
  }
}
$foo = new Foo();

var_dump将输出:

array
  'file' => string '/home/squale/developpement/tests/temp/temp.php' (length=46)
  'line' => int 29
  'function' => string '__construct' (length=11)
  'class' => string 'Foo' (length=3)
  'object' => 
    object(Foo)[1]
  'type' => string '->' (length=2)
  'args' => 
    array
      empty

和echo:

called by Foo :: __construct

但是，尽管看起来不错，但我不确定它是否应该在您的应用程序中用作正常事物" ...似乎有些奇怪，实际上:设计良好的方法不需要知道一种方法在我看来，它叫什么.

But, as nice as it might look like, I am not sure it should be used as a "normal thing" in your application... Seems odd, actually : with a good design, a method should not need to know what called it, in my opinion.

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