将PHP准备的语句与LIKE结合使用 [英] Combine PHP prepared statments with LIKE

问题描述

任何人都知道如何将PHP准备好的语句与LIKE结合起来吗?即

Anyone know how to combine PHP prepared statements with LIKE? i.e.

"SELECT * FROM table WHERE name LIKE %?%";

推荐答案

％符号需要放在您分配给该参数的变量中，而不是查询中.

The % signs need to go in the variable that you assign to the parameter, instead of in the query.

我不知道您使用的是mysqli还是PDO，但是使用PDO就像:

I don't know if you're using mysqli or PDO, but with PDO it would be something like:

$st = $db->prepare("SELECT * FROM table WHERE name LIKE ?");
$st->execute(array('%'.$test_string.'%'));

:为mysqli用户提供以下内容.

EDIT :: For mysqli user the following.

$test_string = '%' . $test_string . '%';
$st->bind_param('s', $test_string);
$st->execute();

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