如何使用URL传递PHP变量 [英] How to pass a PHP variable using the URL
问题描述
我想使用URL传递一些PHP变量.
I want to pass some PHP variables using the URL.
我尝试了以下代码:
link.php
<html>
<body>
<?php
$a='Link1';
$b='Link2';
echo '<a href="pass.php?link=$a">Link 1</a>';
echo '<br/>';
echo '<a href="pass.php?link=$b">Link 2</a>';
?></body></html>`</pre></code>
pass.php
<pre><code>`<html>
<body>
<?php
if ($_GET['link']==$a)
{
echo "Link 1 Clicked";
} else {
echo "Link 2 Clicked";
}
?></body></html>
单击链接Link1和Link2时，出现链接2已单击".为什么?
Upon clicking the links Link1 and Link2, I get "Link 2 clicked". Why?
推荐答案
在您的link.php中，您的echo语句必须像这样:
In your link.php your echo statement must be like this:
echo '<a href="pass.php?link=' . $a . '>Link 1</a>';
echo '<a href="pass.php?link=' . $b . '">Link 2</a>';
然后在pass.php中，您不能使用$a，因为它没有使用预期的字符串值初始化.
Then in your pass.php you cannot use $a because it was not initialized with your intended string value.
您可以将其直接与这样的字符串进行比较:
You can directly compare it to a string like this:
if($_GET['link'] == 'Link1')
另一种方法是首先将变量初始化为与使用link.php相同的操作.而且，更好的方法是将$a和$b变量包含在单个PHP文件中，然后将其包含在所有页面中，您将在这些页面中使用这些变量，如Tim Cooper在他的帖子中提到的那样.您也可以将其包含在会话中.
Another way is to initialize the variable first to the same thing you did with link.php. And, a much better way is to include the $a and $b variables in a single PHP file, then include that in all pages where you are going to use those variables as Tim Cooper mention on his post. You can also include this in a session.
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