如何从字符串中删除所有数字? [英] How to remove all numbers from string?

问题描述

我想删除字符串[0-9]中的所有数字.我写了这段有效的代码:

I'd like to remove all numbers from a string [0-9]. I wrote this code that is working:

$words = preg_replace('/0/', '', $words ); // remove numbers
$words = preg_replace('/1/', '', $words ); // remove numbers
$words = preg_replace('/2/', '', $words ); // remove numbers
$words = preg_replace('/3/', '', $words ); // remove numbers
$words = preg_replace('/4/', '', $words ); // remove numbers
$words = preg_replace('/5/', '', $words ); // remove numbers
$words = preg_replace('/6/', '', $words ); // remove numbers
$words = preg_replace('/7/', '', $words ); // remove numbers
$words = preg_replace('/8/', '', $words ); // remove numbers
$words = preg_replace('/9/', '', $words ); // remove numbers

我想找到一个更优雅的解决方案:1行代码(IMO编写漂亮的代码很重要).

I'd like to find a more elegant solution: 1 line code (IMO write nice code is important).

我在stackoverflow中找到的其他代码也删除了变音符号(á，ñ，ž...).

The other code I found in stackoverflow also remove the Diacritics (á,ñ,ž...).

推荐答案

对于西方阿拉伯数字(0-9):

For Western Arabic numbers (0-9):

$words = preg_replace('/[0-9]+/', '', $words);

对于包括西阿拉伯语在内的所有数字(例如印度):

For all numerals including Western Arabic (e.g. Indian):

$words = '१३३७';
$words = preg_replace('/\d+/u', '', $words);
var_dump($words); // string(0) ""

• \d+匹配多个数字.
• 修饰符/u启用Unicode字符串处理.此修饰符很重要，否则数字将不匹配.
• \d+ matches multiple numerals.
• The modifier /u enables unicode string treatment. This modifier is important, otherwise the numerals would not match.

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