PHP函数替换第(i)个位置字符 [英] PHP function to replace a (i)th-position character

问题描述

PHP中是否有一个函数，该函数接收一个字符串，一个数字(i)和一个字符(x)，然后用(x)替换位置(i)处的字符?

Is there a function in PHP that takes in a string, a number (i), and a character (x), then replaces the character at position (i) with (x)?

如果没有，有人可以帮助我实施它吗?

If not, can somebody help me in implementing it?

推荐答案

$str    = 'bar';
$str[1] = 'A';
echo $str; // prints bAr

或者您可以将库函数substr_replace用作:

or you could use the library function substr_replace as:

$str = substr_replace($str,$char,$pos,1);

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