Symfony2:具有数据原型的收集表单字段类型 [英] Symfony2: collection form field type with data-prototype

问题描述

我有一个要向其添加玩家(玩家的对象)的团队.我已经正确设置了表单类型"类.这是我观点的相关部分:

I have a Team to which I would like to add players (objects of Player). I've set up the form "type" classes correctly. Here's the relevant part of my view:

{% for index, player in form.players %}
    <div id="template" data-prototype="{{ form_widget(form.players.get('prototype')) | e }}">
        <span class="title">{{ index }}</span>
        {{ form_row(player.name) }}
    </div>
{% endfor %}

我的问题是数据原型属性不包含span标记；它仅包含{{ form_row(player.name) }}的输出.有没有办法将div#template的全部内容包含在data-prototype属性中?

My problem is that data-prototype attribute doesn't include the span tag; it only contains the output of {{ form_row(player.name) }}. Is there a way to include the whole content of div#template in the data-prototype attribute?

推荐答案

这也困扰着我.我自定义了字段类型，甚至使用简化的字段集(用于更复杂的对象)制作了简单的表单类型，但是感觉并不对.我想出了一个应该解决这个问题的解决方案:)

This was bugging me too. I customized a field type and even made simple form types with a reduced fieldset (for more complex objects), but it just didn't feel right. I've come up with a solution that should do the trick :)

首先-我认为您的<div id="team" data-prototype="...">应该在循环之外.

First - I think your <div id="team" data-prototype="..."> should be outside your loop.

接下来，您的原型只是一个表单视图对象，因此，如果将其传递给模板，则可以手动呈现字段并自定义输出.注意:自动转义对所包含的内容没有影响，因此请使用过滤器转义".

Next, your prototype is just a form view object, so if you pass it to a template you can render fields by hand and customize the output. Note: autoescape has no effect on included content, so use 'filter escape'.

<div id="playerFields" data-prototype="{% filter escape %}{% include 'AcmeTeamBundle:Team:prototypePlayer.html.twig' with {'form': form.players.get('prototype')} %}{% endfilter %}">

然后在您的prototypePlayer.html.twig中，像平常一样在表单视图中呈现每个字段.

Then in your prototypePlayer.html.twig, just render each field as you normally would in a form view.

<div>
    <span class="title">{{ form_label(form.name) }}</span>
    {{ form_row(form.name) }}
    <span class="age">{{ form_label(form.age) }}</span>
    {{ form_row(form.age) }}
    {# render whatever else you like from your Form/PlayerType class... #}
<div>

我的模板具有与您的问题不同的数据结构，但是应该可以帮助:)

My template has a different data structure to your question, but it should help :)

干杯

克里斯

从Symfony 2.1开始，不推荐使用.get()，并且以上内容均无效.将form.players.get('prototype')替换为form.players.vars.prototype可以在更高版本的Symfony中解决此问题.

As of Symfony 2.1, .get() is deprecated and the above will not work. Replace form.players.get('prototype') with form.players.vars.prototype to fix this in later versions of Symfony.

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