检查一个字符串是否包含多个特定单词 [英] Check if a string contain multiple specific words

问题描述

如何检查字符串是否包含多个特定单词?

How to check, if a string contain multiple specific words?

我可以使用以下代码检查单个单词:

I can check single words using following code:

$data = "text text text text text text text bad text text naughty";
if (strpos($data, 'bad') !== false) {
    echo 'true';
}

但是，我想添加更多单词来检查.像这样:

But, I want to add more words to check. Something like this:

$data = "text text text text text text text bad text text naughty";
if (strpos($data, 'bad || naughty') !== false) {
    echo 'true';
}
?>

(如果找到了这些单词中的任何一个，那么它应该返回true)

(if any of these words is found then it should return true)

但是，以上代码无法正常工作.你知道我在做什么错吗?

But, above code does not work correctly. Any idea, what I'm doing wrong?

推荐答案

为此，您将需要正则表达式和 preg_match 功能.

For this, you will need Regular Expressions and the preg_match function.

类似的东西:

if(preg_match('(bad|naughty)', $data) === 1) { } 

您的尝试失败的原因

正则表达式由PHP regex引擎解析.语法的问题是您使用了||运算符.这不是正则表达式运算符，因此将其计为字符串的一部分.

Regular Expressions are parsed by the PHP regex engine. The problem with your syntax is that you used the || operator. This is not a regex operator, so it is counted as part of the string.

正如上面正确指出的，如果它被视为您要匹配的字符串的一部分:'bad || naughty'作为字符串，而不是表达式！

As correctly stated above, if it's counted as part of the string you're looking to match: 'bad || naughty' as a string, rather than an expression!

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