我想通过PHP从YouTube获取直接URL时出现签名问题 [英] signature issue when I want to get a direct URL from YouTube via PHP
本文介绍了我想通过PHP从YouTube获取直接URL时出现签名问题的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
经过研究，我如何从这样的YouTube视频中获取直接URL:如何从YouTube URL中获取视频的直接URL? [关闭]
after research to how i get direct URL from YouTube videos like this one asking : How to get direct URL of video from YouTube URL? [closed]
我终于做了一个简单的脚本，用php从YouTube视频中生成了一个直接URL. 而且效果很好，但不适用于所有视频
i finally made a simple script to generate a direct URL from YouTube video with php and it works just fine, but not with all videos
不适用于签名"视频，
这是我的代码:
if(isset($_GET['url']) && $_GET['url'] != ""){
parse_str( parse_url( $_GET['url'], PHP_URL_QUERY ), $vars );
$id=$vars['v'];
$dt=file_get_contents("https://www.youtube.com/get_video_info?video_id=$id&el=embedded&ps=default&eurl=&gl=US&hl=en");
//var_dump(explode("&",$dt));
if (strpos($dt, 'status=fail') !== false) {
$x=explode("&",$dt);
$t=array(); $g=array(); $h=array();
foreach($x as $r){
$c=explode("=",$r);
$n=$c[0]; $v=$c[1];
$y=urldecode($v);
$t[$n]=$v;
}
$x=explode("&",$dt);
foreach($x as $r){
$c=explode("=",$r);
$n=$c[0]; $v=$c[1];
$h[$n]=urldecode($v);
}
$g[]=$h;
$g[0]['error'] = true;
$g[0]['instagram'] = "egy.js";
$g[0]['apiMadeBy'] = 'El-zahaby';
echo json_encode($g,JSON_PRETTY_PRINT);
}else{
$x=explode("&",$dt);
$t=array(); $g=array(); $h=array();
foreach($x as $r){
$c=explode("=",$r);
$n=$c[0]; $v=$c[1];
$y=urldecode($v);
$t[$n]=$v;
}
$streams = explode(',',urldecode($t['url_encoded_fmt_stream_map']));
foreach($streams as $dt){
$x=explode("&",$dt);
foreach($x as $r){
$c=explode("=",$r);
$n=$c[0]; $v=$c[1];
$h[$n]=urldecode($v);
}
$g[]=$h;
}
echo json_encode($g,JSON_PRETTY_PRINT);
// var_dump( $g[1]["quality"],true);
}
}else{
@$myObj->error = true;
$myObj->msg = "there is no youtube link";
$myObj->madeBy = "El-zahaby";
$myObj->instagram = "egy.js";
$myJSON = json_encode($myObj,JSON_PRETTY_PRINT);
echo $myJSON;
}
问题示例: https://you-link. herokuapp.com/?url=yt.com?v=csy7cF1T2vk
上的代码: gist.github
任何解决方案?非常感谢
any solution ? thanks a lot
推荐答案
这是从youtube get_video_info
This is another code to get each video qualities from youtube get_video_info
<?php
function YT_IN_DX($url){
$cookie_file_path = "cookies.txt";
$agent = "Mozilla/5.0 (Windows NT 10.0; WOW64; rv:43.0) Gecko/20100101 Firefox/46.0";
$ch = curl_init();
$headers[] = "Connection: Keep-Alive";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file_path);
curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie_file_path);
curl_setopt($ch, CURLOPT_URL, $url);
$res = curl_exec($ch);
curl_close($ch);
return $res;
}
function YT_V_INFO($v){
$url = "https://www.youtube.com/get_video_info?video_id=$v";
$html = urldecode(YT_IN_DX($url));
$video_links = Explode_Content('playabilityStatus', 'adSafetyReason', $html);
$json = str_replace("\u0026", "&", $video_links);
$json = '{"playabilityStatus' . $json . 'adSafetyReason":{"isEmbed":true}}';
$array = json_decode($json, true);
if (isset($array["playabilityStatus"]["status"]) && $array["playabilityStatus"]["status"] == "UNPLAYABLE") {
$data = array("error" => $array["playabilityStatus"]["status"]);
}else{
$formats = $array["streamingData"]["formats"];
for ($a = 0; $a <= (count($formats) - 1); $a++){
$data[] = array(
"url" => $array["streamingData"]["formats"][$a]["url"],
"mimeType" => $array["streamingData"]["formats"][$a]["mimeType"],
"quality" => $array["streamingData"]["formats"][$a]["quality"],
"qualityLabel" => $array["streamingData"]["formats"][$a]["qualityLabel"],
"width" => $array["streamingData"]["formats"][$a]["width"],
"height" => $array["streamingData"]["formats"][$a]["height"],
"audioQuality" => $array["streamingData"]["formats"][$a]["audioQuality"],
"approxDurationMs" => $array["streamingData"]["formats"][0]["approxDurationMs"]
);
}
}
return $data;
}
function Explode_Content($first, $last, $string)
{
$exp = explode($first, $string);
$exp = explode($last, $exp[1]);
return $exp[0];
}
$videoinfo = YT_V_INFO("6chhghoMGVQ");
// $videoinfo=YT_V_INFO("sJsoyuQAepQ");
print_r($videoinfo);
?>
使用这种方法，如果所有者不允许，您将无法获得一些视频ID数据. 这是两个例子:
With this method you can't get some videos ID data, if not allowed by owner. this is two examples :
$videoinfo = YT_V_INFO("6chhghoMGVQ");
输出:
Array
(
[0] => Array
(
[url] => https://r4---sn-p5h-gc5d.googlevideo.com/videoplayback?id=e9c861821a0c1954&itag=18&source=youtube&requiressl=yes&mm=31,26&mn=sn-p5h-gc5d,sn-hpa7znsd&ms=au,onr&mv=m&pl=21&ei=fmWRXLGxLIKZ1wb61YyIBQ&susc=yt&initcwndbps=232500&mime=video/mp4&gir=yes&clen=13861924&ratebypass=yes&dur=276.271&lmt=1448537568788216&mt=1553032481&fvip=4&c=WEB&ip=196.64.208.187&ipbits=0&expire=1553054174&sparams=ip,ipbits,expire,id,itag,source,requiressl,mm,mn,ms,mv,pl,ei,susc,initcwndbps,mime,gir,clen,ratebypass,dur,lmt&signature=E2DEC9FF027D3810BF4309AD81E1C22E51BDA8F8.DCA10F844A294D5D267F518DBF0951B757855D2B&key=yt8
[mimeType] => video/mp4; codecs="avc1.42001E, mp4a.40.2"
[quality] => medium
[qualityLabel] => 360p
[width] => 640
[height] => 360
[audioQuality] => AUDIO_QUALITY_LOW
[approxDurationMs] => 276271
)
[1] => Array
(
[url] => https://r4---sn-p5h-gc5d.googlevideo.com/videoplayback?id=e9c861821a0c1954&itag=22&source=youtube&requiressl=yes&mm=31,26&mn=sn-p5h-gc5d,sn-hpa7znsd&ms=au,onr&mv=m&pl=21&ei=fmWRXLGxLIKZ1wb61YyIBQ&susc=yt&initcwndbps=232500&mime=video/mp4&ratebypass=yes&dur=276.271&lmt=1470942139723144&mt=1553032481&fvip=4&c=WEB&ip=196.64.208.187&ipbits=0&expire=1553054174&sparams=ip,ipbits,expire,id,itag,source,requiressl,mm,mn,ms,mv,pl,ei,susc,initcwndbps,mime,ratebypass,dur,lmt&signature=B99844F18562D76976B29A1E6358A3C6D6A0DA78.CD747441B3C6883D3639B584BDACC4023C0A9082&key=yt8
[mimeType] => video/mp4; codecs="avc1.64001F, mp4a.40.2"
[quality] => hd720
[qualityLabel] => 720p
[width] => 1280
[height] => 720
[audioQuality] => AUDIO_QUALITY_MEDIUM
[approxDurationMs] => 276271
)
[2] => Array
(
[url] => https://r4---sn-p5h-gc5d.googlevideo.com/videoplayback?id=e9c861821a0c1954&itag=43&source=youtube&requiressl=yes&mm=31,26&mn=sn-p5h-gc5d,sn-hpa7znsd&ms=au,onr&mv=m&pl=21&ei=fmWRXLGxLIKZ1wb61YyIBQ&susc=yt&initcwndbps=232500&mime=video/webm&gir=yes&clen=16923548&ratebypass=yes&dur=0.000&lmt=1448363037942780&mt=1553032481&fvip=4&c=WEB&ip=196.64.208.187&ipbits=0&expire=1553054174&sparams=ip,ipbits,expire,id,itag,source,requiressl,mm,mn,ms,mv,pl,ei,susc,initcwndbps,mime,gir,clen,ratebypass,dur,lmt&signature=B477F9D1D7A34ECFAF8C7CDBC94A46B365633A26.DEC0E30537E6DE02FD960E515CC5DDB4CFEFC65C&key=yt8
[mimeType] => video/webm; codecs="vp8.0, vorbis"
[quality] => medium
[qualityLabel] => 360p
[width] => 640
[height] => 360
[audioQuality] => AUDIO_QUALITY_MEDIUM
[approxDurationMs] => 276271
)
)
这是他的所有者不允许的另一个视频ID.
This is another video ID not allowed by his owner.
$videoinfo=YT_V_INFO("sJsoyuQAepQ");
输出:
数组( [错误] =>无法播放)
Array ( [error] => UNPLAYABLE )
这篇关于我想通过PHP从YouTube获取直接URL时出现签名问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
