DateTime类创建一个函数，在考虑到工作时间和保持时间的情况下，在截止日期前添加小时 [英] DateTime class create a function to add hours onto a deadline taking into account working hours and on hold time
问题描述
基本上，我正在尝试创建一个基本的案件记录系统，当有人打开一个新案件时，该案件被分配了给定的小时数优先级.例如，优先级1是4小时，2是9小时，3是36小时，4是63小时.
Basically I am trying to create a basic case logging system and when somebody opens a new case, the case is assigned a priority with a given number of hours. For example priority 1 is 4 hours, 2 is 9 hours, 3 is 36hours and 4 is 63 hours.
现在将时间添加到时间戳上很容易，但是要注意的是，我需要考虑周一至周五的08:30至17:30的工作时间.因此，如果将一个案例的优先级设为4小时，并且截止日期为工作日的17:30之后，则截止日期将延长至下一个工作日.截止日期基本上是4个工作小时.
Now adding hours onto a time stamp is easy but the catch is I need to take into account working hours which are 08:30 to 17:30 Monday to Friday. So if a case is given a 4 hour priority and the deadline for this falls after 17:30 on a week day then the deadline is extended to the next working day. Basically the deadline is 4 working hours.
示例:
案例创建于:19/05/2014 16:55-优先级1(4小时) 截止日期为:20/05/2014 11:55
Case created on: 19/05/2014 16:55 - with Priority 1 (4 Hours) Deadline is now: 20/05/2014 11:55
有道理吗?
另一个问题是我需要考虑保留时间，而这两个时间只能在工作时间之内.但是以后会担心.
Another catch is I need to take into account hours On Hold and these two have to be only within working hours. But ill worry about that later.
我正在尝试为此使用现代的DateTime类.
I am trying to use the modern DateTime class for this as far as possible.
到目前为止，这是我所要解决的问题，我在逻辑上苦苦挣扎.如果截止日期是一天之内，它会起作用，但是如果我添加了63个小时，它将在星期日返回.
Here is what I have so far, I am struggling with the logic. It works if the deadline is within a day but if I add something like 63 hours it returns back on a Sunday.
我在哪里错了?炸了这个:(
Where am I going wrong here? Brain is fried with this :(
<?php
function addRollover($givenDate, $addtime) {
$datetime = new DateTime($givenDate);
$datetime->modify($addtime);
if (in_array($datetime->format('l'), array('Sunday','Saturday')) ||
17 < $datetime->format('G') ||
(17 === $datetime->format('G') && 30 < $datetime->format('G'))
) {
$endofday = clone $datetime;
$endofday->setTime(17,30);
$interval = $endofday->diff($datetime);
$datetime->add(new DateInterval('P1D'));
if (in_array($datetime->format('l'), array('Saturday', 'Sunday'))) {
$datetime->modify('next Monday');
}
$datetime->setTime(8,30);
$datetime->add($interval);
}
return $datetime;
}
//this is returning back 2014-06-29 17:41:00 which is a sunday.
$future = addRollover('2014-06-26 11:41:00', '+63 hours');
echo $future->format('Y-m-d H:i:s');
查看实际运行情况: http://3v4l.org/Ac8ro
以下是该函数应该发生的情况的说明:
Here's an explanation of what's supposed to be going on in the function:
首先，我们创建一个代表开始日期/时间的DateTime对象
First we create a DateTime object representing our starting date/time
然后，我们向其中添加指定的时间量(请参阅支持的日期和时间格式)
We then add the specified amount of time to it (see Supported Date and Time Formats)
我们检查一下是周末，下午6点之后还是下午5点(超过30点) 分钟过去了(例如，下午5:30之后)
We check to see if it is a weekend, after 6PM, or in the 5PM hour with more than 30 minutes passed (e.g. after 5:30PM)
如果是这样，我们克隆日期时间对象并将其设置为5:30 PM
If so we clone our datetime object and set it to 5:30PM
然后，我们将结束时间(5:30 PM)与修改后的时间之间的差值作为DateInterval对象获取
We then get the difference between the end time (5:30PM) and the modified time as a DateInterval object
然后我们进行到第二天
如果第二天是星期六，我们将进行到第二天
If the next day is a Saturday we progress to the next day
如果第二天是星期日，我们将进行到第二天
If the next day is a Sunday we progress to the next day
然后我们将时间设置为8:30 AM
We then set our time to 8:30AM
然后，将结束时间(5:30 PM)与修改后的时间之间的差值添加到datetime对象
We then add our difference between the end time (5:30PM) and the modified time to our datetime object
我们从函数中返回对象
推荐答案
更新2
根据提供的建议更新了代码
UPDATE 2
Updated the code as per based on suggestions provided
<?php
function addRollover($givenDate, $addtime, $dayStart, $dayEnd, $weekDaysOnly) {
//Break the working day start and end times into hours, minuets
$dayStart = explode(',', $dayStart);
$dayEnd = explode(',', $dayEnd);
//Create required datetime objects and hours interval
$datetime = new DateTime($givenDate);
$endofday = clone $datetime;
$endofday->setTime($dayEnd[0], $dayEnd[1]); //set end of working day time
$interval = 'PT'.$addtime.'H';
//Add hours onto initial given date
$datetime->add(new DateInterval($interval));
//if initial date + hours is after the end of working day
if($datetime > $endofday)
{
//get the difference between the initial date + interval and the end of working day in seconds
$seconds = $datetime->getTimestamp()- $endofday->getTimestamp();
//Loop to next day
while(true)
{
$endofday->add(new DateInterval('PT24H'));//Loop to next day by adding 24hrs
$nextDay = $endofday->setTime($dayStart[0], $dayStart[1]);//Set day to working day start time
//If the next day is on a weekend and the week day only param is true continue to add days
if(in_array($nextDay->format('l'), array('Sunday','Saturday')) && $weekDaysOnly)
{
continue;
}
else //If not a weekend
{
$tmpDate = clone $nextDay;
$tmpDate->setTime($dayEnd[0], $dayEnd[1]);//clone the next day and set time to working day end time
$nextDay->add(new DateInterval('PT'.$seconds.'S')); //add the seconds onto the next day
//if the next day time is later than the end of the working day continue loop
if($nextDay > $tmpDate)
{
$seconds = $nextDay->getTimestamp()-$tmpDate->getTimestamp();
$endofday = clone $tmpDate;
$endofday->setTime($dayStart[0], $dayStart[1]);
}
else //else return the new date.
{
return $endofday;
}
}
}
}
return $datetime;
}
$currentTime = '2014-06-27 08:30:00';
$dayStart = '8,30';
$dayEnd = '17,30';
$future = addRollover($currentTime, 65, $dayStart, $dayEnd, true);
echo "Results: </br>";
echo $future->format('Y-m-d H:i:s').'</br>';
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