在非对象上调用fetch_assoc()是否失败? [英] Call to fetch_assoc() on a non-object failing?
本文介绍了在非对象上调用fetch_assoc()是否失败?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在phpMyAdmin中创建了一个名为"whatevers"的表.您可以看到它的内容
I have created a table in my phpMyAdmin called 'whatevers'. You can see the contents of it
.
我正在尝试从该表中获取所有条目(记录?)并回显它们.
I'm trying to fetch all the entries (records?) out of this table and echo them.
这是我尝试使用的代码:
This is the code I have attempted to do this with:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Welcome to <? print $host; ?>!</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<?php
$servername = "mysql.hostinger.co.uk";
$username = "u427788796_h4x1t";
$password = "********";
$dbname = "u427788796_db";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
////
$sql = "SELECT * FROM `whatevers` LIMIT 0, 30 ";
//echo $sql;
while ($row = $sql->fetch_assoc()) {
echo $row['classtype']."<br>";
}
mysqli_close($conn);
?>
</body>
</html>
这是失败的，因为我收到了错误消息:
This is failing as I am getting the error message:
致命错误:在第30行的/home/u427788796/public_html/default.php中的非对象上调用成员函数fetch_assoc()
推荐答案
已调用方法查询
$sql = $conn->query("SELECT * FROM `whatevers` LIMIT 0, 30 ");
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